NEET Questions

The masses of two planets are in the ratio $1:2$. Their radii are in the ratio $1:2$. The acceleration due to gravity on the planets are in the ratio

Acceleration due to gravity is $g$ on the surface of the earth. Then the value of the acceleration due to gravity at a height of 32 km above earth’s surface is (Assume radius of earth to be 6400 km)

A body is taken to a height of $nR$ from the surface of the earth. The ratio of the acceleration due to gravity on the surface to that at the altitude is

The acceleration due to gravity about the earth’s surface would be half of its value on the surface of the earth at an altitude of $\left( {R = 4000\;mile} \right)$

The speed of earth’s rotation about its axis is $\omega$. Its speed is increased to $x$ times to make the effective acceleration due to gravity equal to zero at the equator, then $x$ is around $\left( {{\rm{g}} = 10{\rm{m}}{{\rm{s}}^{ - 2}},R = 6400\;{\rm{km}}} \right)$

The depth from the surface of the earth of radius $R$ at which the acceleration due to gravity will be $75\%$ of the value on the surface of the earth is

If a planet consists of a satellite whose mass and radius were both half that of the earth, the acceleration due to gravity at its surface would be (g on earth $= 9.8\;m/{\rm{se}}{{\rm{c}}^2}$)

What will be the acceleration due to gravity at height $h$ if $h > \; > R$. Where $R$ is radius of earth and $g$ is acceleration due to gravity on the surface of earth

The value of '$g$' at a particular point is $9.8\;m/{s^2}$. Suppose the earth suddenly shrinks uniformly to half its present size without losing any mass. The value of '$g$' at the same point (assuming that the distance of the point from the centre of earth does not shrink) will now be

320 km above the surface of earth, the value of acceleration due to gravity is nearly $90\%$ of its value on the surface of the earth. Its value will be $95\%$ of the value on the earth’s surface