NEET Questions

If at a small height $h$ above the surface of earth acceleration due to gravity decreases by $0.2 \%$, then at depth $h$ below the surface of earth, the acceleration due to gravity will

At what height from above the surface of earth, then value of acceleration due to gravity reduces to half of its present value (radius of earth - $6400 \mathrm{~km}$)

The acceleration to gravity at a height $1 / 20^{ext {th }}$ of the radius of the earth above the earth surface. is $9 {~ms}^{-2}$. It value at a point at an equal distance below the surface of the earth in ${ms}^{-2}$ is about

The height above surface of earth where the value of gravitational acceleration is the value of

gravitational acceleration is one fourth of that at surface, will be

The weight of a body at earth's surface is $W$. At a depth halfway to the centre of the earth, it will be (assuming uniform density in the earth)

In a vertical spring mass system if stretching in spring at equilibrium near earth surface is $x_0$ then the extension in spring at a height $1600 \mathrm{~km}$ from earth surface is (radius of earth $R=6400 \mathrm{~km}$ )

A simple pendulum is taken to $64 \mathrm{~km}$ above the earth's surface. Its new time period will

The earth's radius is ${R}$ and acceleration due to gravity at its surface is ${g}$. If a body of mass ${m}$ is sent to a height of $\frac{{R}}{4}$ from the earth's surface, the potential energy increases by:

If at depth $(h)$, acceleration due to gravity decreases by $25 \%$ as compared to surface of earth, then at height $(h)$ it will decrease by (in comparison with surface of earth)

The change in the value of $g$ at a height $h$ above the earth's surface is the same as that at a depth $d$ below the earth's surface. Here both $h$ and $d$ are very small as compared to the radius of the earth. The relation between $d$ and $h$ will be