Name the metal $M$ which is extracted on the basis of following reactions, $4M + 8{\rm{C}}{{\rm{N}}^ - } + 2{{\rm{H}}_2}{\rm{O}} + {{\rm{O}}_2} \to 4{\left[ {M{{\left( {{\rm{CN}}} \right)}_2}} \right]^ - } + 4{\rm{O}}{{\rm{H}}^ - }$ $2{\left[ {M{{\left( {{\rm{CN}}} \right)}_2}} \right]^ - } + {\rm{Zn}} \to {\left[ {{\rm{Zn}}{{\left( {{\rm{CN}}} \right)}_4}} \right]^{2 - }} + 2M$:

## CORE INFORMATION\n✓ **Answer**: B\n## CONCEPT FRAMEWORK\n**Primary Concept**: Metal extraction using complex formation and displacement.\n**Related Topics**: Coordination chemistry, redox reactions, metallurgy.\n**Prerequisites**: Knowledge of metal extraction processes, complex ion formation, reactivity series of metals.\n## SOLUTION PATHWAY\n**Given Information**:\nReactions:\n 1. $4M + 8CN^- + 2H_2O + O_2 \to 4[M(CN)_2]^- + 4OH^-$\n 2. $2[M(CN)_2]^- + Zn \to [Zn(CN)_4]^{2-} + 2M$\n**Method & Steps**:\n1. **Identify the type of reaction**: The first reaction shows the metal (M) forming a complex ion with cyanide. The second reaction shows the displacement of M by Zinc.\nReasoning: Metals like gold and silver form stable cyanide complexes in presence of air and water. Zinc is more reactive than gold and silver and can displace them from their cyanide complexes.\nFormula/Rule: Reactivity series of metals.\n2. **Analyze the displacement**: The second reaction shows that Zinc displaces metal M from its complex, which suggests that Zinc is more reactive than M. This narrows down the possibilities.\nWorking: Zinc is more reactive than silver and gold but less reactive than copper and nickel.\nKey Point: The displacement of metal by zinc indicates that metal must be less reactive than zinc.\n3. **Determine the metal**: Considering the common extraction methods, the metal that is extracted using cyanide complex formation and subsequent displacement by zinc is silver.\nResult: The metal M is Silver.\nVerification: Silver is extracted using the cyanide process.\n## OPTION ANALYSIS\n[A] :x: Nickel does not form this specific type of complex in the given context and is not typically extracted in this manner.\n[B] ✓: Silver forms a stable cyanide complex, which is then reduced by zinc to yield metallic silver.\n[C] :x: Copper is not typically extracted using this cyanide method. It's extracted using other methods like roasting and electrolysis.\n[D] :x: Mercury does not form cyanide complexes, and its extraction involves different methods (amalgamation).\n## LEARNING AIDS\n**Common Mistakes**:\n1. **Confusing metal reactivities**: Incorrectly assigning the reactivity of metals like copper, nickel, or mercury in the context of extraction.\nHow to avoid: Review the reactivity series of metals and their typical extraction methods.\n2. **Incorrectly identifying the complex**: Mistaking the complex formed or the displacement reaction.\nHow to avoid: Practice identifying common complex ions and their formation reactions.\n**Quick Tips**:\n1. **Cyanide process**: Remember that the cyanide process is predominantly used for the extraction of gold and silver.\n2. **Displacement Reactions**: More reactive metals displace less reactive metals from their salt solutions or complexes.

NEET Chemistry Coordination Compounds MCQs

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Organo Metallic Compounds & Importance Of Coordination Compounds

71.

The oxidation number of ${\rm{Fe}}$ in ${{\rm{K}}_4}\left[ {{\rm{Fe}}{{\left( {{\rm{CN}}} \right)}_6}} \right]\,{\rm{is}}$

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Question Tags

📚 Subject:Chemistry

📑 Chapter:Coordination Compounds

🎯Topic:Werner'S Theory

🎓 Ncert Level:Application

🎯Difficulty :Easy

⚡ Time Required :2 mins

🔄Ncert Concepts :oxidation number, coordination complex, charge neutrality

72.

Name the metal $M$ which is extracted on the basis of following reactions, $4M + 8{\rm{C}}{{\rm{N}}^ - } + 2{{\rm{H}}_2}{\rm{O}} + {{\rm{O}}_2} o 4{\left[ {M{{\left( {{\rm{CN}}} \right)}_2}} \right]^ - } + 4{\rm{O}}{{\rm{H}}^ - }$ $2{\left[ {M{{\left( {{\rm{CN}}} \right)}_2}} \right]^ - } + {\rm{Zn}} o {\left[ {{\rm{Zn}}{{\left( {{\rm{CN}}} \right)}_4}} \right]^{2 - }} + 2M$ :