The time period of a simple pendulum is given by T=2πlg+kxT = 2\pi\sqrt{\frac{l}{g}} + kxT=2πgl+kx, where lll is the length, ggg is acceleration due to gravity, and xxx is displacement. The dimensions of kkk are:
[L⁻¹T]
[LT⁻¹]
[L⁻¹T⁻¹]
[L⁻²T²]
Related Questions
Consider a new system of units in which c(speed of light in vacuum), h(Planck’s constant) and G(gravitational constant) are taken as fundamental units. Which of the following would correctly represent mass in this new system?
hcG\sqrt {\frac{{hc}}{G}} Ghc
Gch\sqrt {\frac{{Gc}}{h}} hGc
hGc\sqrt {\frac{{hG}}{c}} chG
hGc\sqrt {hGc} hGc