NEET Questions

The ratio of gravitational potential to acceleration due to gravity at a certain height above Earth is $-9.5 imes 10^6$ m. If Earth's radius is 6400 km, what is that height?

At what height above the Earth's surface will the gravitational potential be $-4 imes 10^7 \, J \, kg^{-1}$, if the acceleration due to gravity at that height is half the value of g at the surface (9.8 m/s\u00b2)? (Take Earth's radius as 6400 km)

The acceleration due to gravity at a height of 500 m above the Earth is the same as at a depth 'd' below the surface of the Earth. What is the approximate value of 'd'? (Assume Earth's radius $R = 6400$ km)

At what height above the Earth's surface is the acceleration due to gravity equal to the acceleration due to gravity at a depth of 2 km below the surface? (Assume Earth's radius is much larger than 2 km)

The gravitational acceleration at a height 'h' above the Earth's surface is $9.78 \frac{m}{s^2}$. If the acceleration due to gravity at a depth 'd' below the surface is also $9.78 \frac{m}{s^2}$, and the acceleration due to gravity at the surface is $9.8 \frac{m}{s^2}$, find the relationship between h and d. (Assume Earth's radius $R = 6400$ km)

If the acceleration due to gravity is the same at a height 'h' and a depth 'd' from the Earth's surface, which of the following is true? (Consider Earth to be a uniform sphere.)

A planet has a radius 'R'. The acceleration due to gravity is found to be the same at a height 'x' above the surface and a depth 'y' below the surface. What is the relationship between x and y?

How does the acceleration due to gravity (g) vary with distance (r) from the center of the Earth, considering the Earth's radius as R?

If the Earth's radius is R, at what distance from the Earth's center is the acceleration due to gravity (g) maximum?

The acceleration due to gravity at a depth 'd' from the Earth's surface is given by?