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    21.

    Given that the dimensions of angular momentum are [ML2^2T−1^{-1}] and those of action are [ML2^2T−1^{-1}], which of the following quantities is dimensionless?

    A

    Angular momentum x Action

    B

    Angular momentum + Action

    C

    Angular momentum / Action

    D

    Angular momentum - Action

    Question Tags

    📚 Subject:Physics
    📑 Chapter:Units And Measurement
    🎯Topic:Dimensional Formula
    🎓 Ncert Level:Analyzing
    🎯Difficulty :Hard
    ⚡ Time Required :1 mins
    🔄Ncert Concepts :Dimensional Formula, Angular Momentum, Action, Principle of Homogeneity
    22.

    If the velocity v(is  cms−1)v\left( {{\rm{is\;cm}}{{\rm{s}}^{ - 1}}} \right) of a particle is given in terms of t (in second) by the relation     v=at+bt+c\;\;v = at + \frac{b}{{t + c}} then, the dimensions of a,b and c are

    A

    a = [L]  \left[ {\rm{L}} \right]{\rm{\;}}, b =   [LT]{\rm{\;}}\left[ {{\rm{LT}}} \right], c = [T2]\left[ {{{\rm{T}}^2}} \right]

    B

    a = [L2]\left[ {{{\rm{L}}^2}} \right], b = [T]  \left[ {\rm{T}} \right]{\rm{\;}}, c = [LT−2]\left[ {{\rm{L}}{{\rm{T}}^{ - 2}}} \right] 

    C

    a = [LT2]\left[ {{\rm{L}}{{\rm{T}}^2}} \right], b = [LT]\left[ {{\rm{LT}}} \right], c = [L]\left[ {\rm{L}} \right]

    D

    a = [LT−2]\left[ {{\rm{L}}{{\rm{T}}^{ - 2}}} \right], b = [L]  \left[ {\rm{L}} \right]{\rm{\;}}, c = [T]\left[ {\rm{T}} \right]

    Question Tags

    📚 Subject:Physics
    📑 Chapter:Units And Measurement
    🎯Topic:Limitations Of Dimensional Analysis
    🎓 Ncert Level:Application
    🎯Difficulty :Medium
    ⚡ Time Required :3 mins
    🔄Ncert Concepts :Dimensional Analysis, Principle of Homogeneity
    23.

    If the velocity v(is  cms−1)v\left( {{\rm{is\;cm}}{{\rm{s}}^{ - 1}}} \right) of a particle is given in terms of t (in second) by the relation     v=at+bt+c\;\;v = at + \frac{b}{{t + c}} then, the dimensions of a,b and c are

    A

    a = [L]  \left[ {\rm{L}} \right]{\rm{\;}}, b =   [LT]{\rm{\;}}\left[ {{\rm{LT}}} \right], c = [T2]\left[ {{{\rm{T}}^2}} \right]

    B

    a = [L2]\left[ {{{\rm{L}}^2}} \right], b = [T]  \left[ {\rm{T}} \right]{\rm{\;}}, c = [LT−2]\left[ {{\rm{L}}{{\rm{T}}^{ - 2}}} \right] 

    C

    a = [LT2]\left[ {{\rm{L}}{{\rm{T}}^2}} \right], b = [LT]\left[ {{\rm{LT}}} \right], c = [L]\left[ {\rm{L}} \right]

    D

    a = [LT−2]\left[ {{\rm{L}}{{\rm{T}}^{ - 2}}} \right], b = [L]  \left[ {\rm{L}} \right]{\rm{\;}}, c = [T]\left[ {\rm{T}} \right]

    Question Tags

    📚 Subject:Physics
    📑 Chapter:Units And Measurement
    🎯Topic:Limitations Of Dimensional Analysis
    🎓 Ncert Level:Application
    🎯Difficulty :Medium
    ⚡ Time Required :3 mins
    🔄Ncert Concepts :Dimensional Analysis, Principle of Homogeneity

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