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A potentiometer wire of length 100 cm has a resistance of 10 Ω. It is connected in series with a resistance box and a 2V cell of negligible internal resistance. If a cell of emf E1E_1E1 is balanced against a length of 40 cm and another cell of emf E2E_2E2 is balanced against a length of 60 cm when the resistance in the box is 10 Ω and 5 Ω respectively, the ratio E1E2\frac{E_1}{E_2}E2E1 is:
1/2
1/3
2/3
3/4
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