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    73.

    A block is projected up a rough inclined plane with an initial velocity uu. The coefficient of kinetic friction between the block and the plane is μk\mu_k. The block travels a distance ss up the plane before coming to rest. What is the angle of inclination hetaheta of the plane?

    A

    \sinheta+μk\cosheta=2gsu2\sinheta + \mu_k\cosheta = \frac{2gs}{u^2}

    B

    \sinhetaμk\cosheta=u22gs\sinheta - \mu_k\cosheta = \frac{u^2}{2gs}

    C

    \sinheta+μk\cosheta=u2gs\sinheta + \mu_k\cosheta = \frac{u^2}{gs}

    D

    \sinheta+μk\cosheta=u22gs\sinheta + \mu_k\cosheta = \frac{u^2}{2gs}

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    74.

    A block of mass mm rests on a horizontal surface with coefficient of static friction μs\mu_s. A force FF is applied at an angle hetaheta to the horizontal. The minimum force required to just move the block is:

    A

    Fmin=μsmgF_{min} = \mu_s mg

    B

    Fmin=μsmg\coshetaF_{min} = \frac{\mu_s mg}{\cosheta}

    C

    Fmin=μsmg\sinhetaF_{min} = \frac{\mu_s mg}{\sinheta}

    D

    Fmin=μsmg\cosheta+μs\sinhetaF_{min} = \frac{\mu_s mg}{\cosheta + \mu_s \sinheta}

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    75.

    A car is moving with uniform speed on a banked road inclined at an angle hetaheta. The coefficient of static friction between the tyres and road is μs\mu_s. What is the maximum speed with which the car can negotiate the curve without skidding, if the radius of the curve is RR?

    A

    vmax=Rganhetav_{max} = \sqrt{Rganheta}

    B

    vmax=μsRgv_{max} = \sqrt{\mu_s Rg}

    C

    vmax=Rg\sinheta+μs\cosheta\coshetaμs\sinhetav_{max} = \sqrt{Rg\frac{\sinheta + \mu_s\cosheta}{\cosheta - \mu_s\sinheta}}

    D

    vmax=Rg\cosheta+μs\sinheta\sinhetaμs\coshetav_{max} = \sqrt{Rg\frac{\cosheta + \mu_s\sinheta}{\sinheta - \mu_s\cosheta}}

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    76.

    A block of mass mm is placed on a rough rotating disc at a distance rr from the center. The coefficient of static friction is μs\mu_s. What is the maximum angular speed ω\omega for which the block will not slip?

    A

    ωmax=μsgr\omega_{max} = \sqrt{\mu_s gr}

    B

    ωmax=μsgr\omega_{max} = \frac{\mu_s g}{r}

    C

    ωmax=μsgr\omega_{max} = \sqrt{\frac{\mu_s g}{r}}

    D

    ωmax=rμsg\omega_{max} = \sqrt{\frac{r}{\mu_s g}}

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    77.

    A particle moves in a plane with a velocity given by v=(Aωcos(ωt))i^+(Bωsin(ωt))j^\vec{v} = (A\omega cos(\omega t))\hat{i} + (B\omega sin(\omega t))\hat{j}. If the particle starts from the origin at t=0t=0, the equation of the trajectory is:

    A

    x2A2+y2B2=1\frac{x^2}{A^2} + \frac{y^2}{B^2} = 1

    B

    x2A2+(1yB)2=1\frac{x^2}{A^2} + \left(1 - \frac{y}{B}\right)^2 = 1

    C

    x2A2+(yB)2B2=1\frac{x^2}{A^2} + \frac{(y-B)^2}{B^2} = 1

    D

    x2A2+y2B2=2\frac{x^2}{A^2} + \frac{y^2}{B^2} = 2

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