1.

    A block of mass mm is placed on a rough inclined plane with an angle of inclination hetaheta. The coefficient of static friction between the block and the plane is μs\mu_s. A horizontal force FF is applied to the block. For what range of values of FF will the block remain at rest?

    A

    mg(sinθ - μs cosθ)/(cosθ + μs sinθ) ≤ F ≤ mg(sinθ + μs cosθ)/(cosθ - μs sinθ)

    B

    mg(sinθ - μk cosθ)/(cosθ + μk sinθ) ≤ F ≤ mg(sinθ + μk cosθ)/(cosθ - μk sinθ)

    C

    F ≤ mg(sinθ + μs cosθ)/(cosθ - μs sinθ)

    D

    F ≥ mg(sinθ - μs cosθ)/(cosθ + μs sinθ)

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    3.

    Which of the following statements is true about the static frictional force acting on a stationary object on a rough surface?

    A

    It is always zero.

    B

    It is equal to the applied force if the object is not moving.

    C

    It is greater than the kinetic friction.

    D

    It is independent of the roughness of the surface.

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    7.

    A stationary body of mass 3 kg explodes into three equal pieces. Two of the pieces fly off in two mutually perpendicular directions, one with velocity of 3  i^  ms13\;\hat i\;{\rm{m}}{{\rm{s}}^{ - 1}} and the other with a velocity of 4  j^ms14\;\hat j\,{\rm{m}}{{\rm{s}}^{ - 1}} . If the explosion occurs in 104{10^{ - 4}} s, the force acting on the third piece in newtons is

    A

    (3  i^+4  j^)imes104\left( {3\;\hat i + 4\;\hat j} \right) imes {10^{ - 4}}

    B

    (3  i^4  j^)imes104\left( {3\;\hat i - 4\;\hat j} \right) imes {10^{ - 4}}

    C

    (3  i^+4  j^)imes104\left( {3\;\hat i + 4\;\hat j} \right) imes {10^4}

    D

    (3  i^+4  j^)imes104 - \left( {3\;\hat i + 4\;\hat j} \right) imes {10^4}

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    9.

    A car is moving with uniform speed on a banked road inclined at an angle hetaheta. The coefficient of static friction between the tyres and road is μs\mu_s. What is the maximum speed with which the car can negotiate the curve without skidding, if the radius of the curve is RR?

    A

    vmax=Rganhetav_{max} = \sqrt{Rganheta}

    B

    vmax=μsRgv_{max} = \sqrt{\mu_s Rg}

    C

    vmax=Rg\sinheta+μs\cosheta\coshetaμs\sinhetav_{max} = \sqrt{Rg\frac{\sinheta + \mu_s\cosheta}{\cosheta - \mu_s\sinheta}}

    D

    vmax=Rg\cosheta+μs\sinheta\sinhetaμs\coshetav_{max} = \sqrt{Rg\frac{\cosheta + \mu_s\sinheta}{\sinheta - \mu_s\cosheta}}

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