A plant cell is placed in a solution with a water potential of -0.8 MPa. The cell's initial solute potential is -1.2 MPa and its pressure potential is 0.4 MPa. After equilibration, which of the following statements about the cell's state is MOST accurate?
The cell will be turgid, with a pressure potential greater than 0.4 MPa.
The cell will be flaccid, with a pressure potential of zero.
The cell will be plasmolyzed, with a pressure potential of zero.
The cell will experience incipient plasmolysis, with a pressure potential slightly above zero.
Related Questions
    If turgidity of a cell surrounded by water increases, the wall pressure will
    Increase
Decrease
Fluctuate
Remain unchanged
In plasmolysed cell, the space between nucleus and plasma membrane is occupied by
Hypotonic solution
Hypertonic solution
Isotonic solution
Air
What is the driving force behind plasmolysis?
Diffusion
Active transport
Osmosis
Facilitated diffusion
    When plant cell is kept in saline drip, cell
    Decrease in size
Bursts out
Increase in size
Unchanged
    The pressure exerted by the protoplast due to the entry of water against the rigid cell wall is termed as
Turgor pressure
Osmotic potential
Solute potential
Water potential
Plasmolysed cell become completely deplasmolysed when kept in
Dilute salt solvent
Concentrated salt water
Pure water
none of these
If the cell is placed in hypotonic solution what will happen?
Endosmosis
Exosmosis
Deplasmolysis
No change
The space between the plasma membrane and the cell wall of a plasmolyzed cell surrounded by a hypertonic solution is occupied by the
Hypotonic solution
Isotonic solution
Hypertonic solution
Water
    What will happen, if a large amount of water enters in a plant cell?
TP of cell gets reduced
TP opposes the entry of water
Water potential of the cell become more negative
    Water potential of the cell increases simultaneously
    When plant cell is kept in saline drip, cell
    Decrease in size
Bursts out
Increase in size
Unchanged
