Two forces, $\vec{P}$ and $\vec{Q}$, act at a point. If the magnitude of their resultant is equal to the magnitude of $\vec{P}$ and perpendicular to $\vec{P}$, and the magnitude of $\vec{Q}$ is $Q$, what is the magnitude of $\vec{P}$?

The resultant of two forces, one doubled the other in magnitude is perpendicular to the smaller of the forces. The angle between the two forces is

Two forces of 5 N and 10 N act on a point at an angle of 60 degrees. According to the parallelogram law, what is the magnitude of their resultant?

Two forces, each of magnitude F, act on a point. If the angle between them is doubled, what happens to the magnitude of their resultant?

Two forces, each of magnitude $F$, act at a point at an angle $heta$. If the resultant force has the same magnitude $F$, the angle $heta$ is:

If three vectors acting simultaneously on a particle can be represented in magnitude and direction by the three sides of a triangle taken in order, then the particle will:

The parallelogram law of vector addition is equivalent to which other method of vector addition?

The adjacent sides of a parallelogram are $\overrightarrow A = 2\widehat i - 3\widehat j + \widehat k\,and\,\overrightarrow B = - 2\widehat i + 4\widehat j - \widehat k$ . Then the area of the parallelogram is

Two forces of equal magnitude F act on an object. For which angle between the forces will the magnitude of the resultant be maximum?

Two forces of magnitudes $F_1$ and $F_2$ act on a particle. The resultant force has a magnitude $F_R$. If the angle between $F_1$ and $F_2$ is increased, keeping their magnitudes constant, which of the following is true about the magnitude of the resultant force $F_R$?

Which law states that the resultant of two vectors represented in magnitude and direction by the adjacent sides of a parallelogram is given by the diagonal of the parallelogram?