Two vectors $\vec{A}$ and $\vec{B}$ are added using the parallelogram law. If the magnitude of $\vec{A}$ is doubled while keeping the magnitude of $\vec{B}$ and the angle between them constant, how does the magnitude of the resultant vector change?

Two forces of magnitudes $F_1$ and $F_2$ act on a particle. The resultant force has a magnitude $F_R$. If the angle between $F_1$ and $F_2$ is increased, keeping their magnitudes constant, which of the following is true about the magnitude of the resultant force $F_R$?

Two forces, each of magnitude $F$, act at a point at an angle $heta$. If the resultant force has the same magnitude $F$, the angle $heta$ is:

The adjacent sides of a parallelogram are $\overrightarrow A = 2\widehat i - 3\widehat j + \widehat k\,and\,\overrightarrow B = - 2\widehat i + 4\widehat j - \widehat k$ . Then the area of the parallelogram is

Two forces, each of magnitude F, act on a point. If the angle between them is doubled, what happens to the magnitude of their resultant?

If the sum of two unit vectors is a unit vector, then magnitude of difference is

Two forces of 5 N and 10 N act on a point at an angle of 60 degrees to each other. What is the magnitude of their resultant force?

Two forces of 6 N and 8 N act at a point at right angles to each other. What is the magnitude of their resultant force?

The adjacent sides of a parallelogram are $\overrightarrow A = 2\widehat i - 3\widehat j + \widehat k\,and\,\overrightarrow B = - 2\widehat i + 4\widehat j - \widehat k$ . Then the area of the parallelogram is

If two vectors of 3 N and 4 N are acting at right angles to each other, what is the magnitude of their resultant?

If the sum of the two unit vectors is also a unit vector, then magnitude of their difference is