The vector product of two vectors $\vec{A}$ and $\vec{B}$ has a magnitude of $AB$. What is the angle between them?

If ${\rm{\vec A}}{\rm{.\vec B}} = 0\,and\,\,{\rm{\vec A}} imes {\rm{\vec B}} = 1$, then ${\rm{\vec A}}\;\,and\,{\rm{\vec B}}$ are

The component of $\overrightarrow A$ along $\overrightarrow B$ is 2 times that of the component of $\overrightarrow B$ along $\overrightarrow A$. Then A : B is

Given ${\rm{\vec P}} = 3\hat j + 4\hat k\,and\,{\rm{\vec Q}} = 2\hat i + 5\hat k$. The magnitude of the scalar product of these vectors is

A vector $\overrightarrow A$ points vertically upward and $\overrightarrow B$ points towards north. The vector product of $\overrightarrow A \, imes \,\overrightarrow B$ is

The resultant of two vector of equal magnitude is twice of magnitude of either of the vectors the angle between them is

If $\overrightarrow F = \widehat i + 2\widehat j - 3\widehat k$ and $\overrightarrow r = 2\widehat i - \widehat j + \widehat k$. Find $\overrightarrow r imes \overrightarrow F$

If ${\rm{\vec A}}{\rm{.\vec B}} = AB,$, then the angle between ${\rm{\vec A}}\,{\rm{and}}\,{\rm{\vec B}}$ is

Consider a vector $\overrightarrow F = 4\widehat i - 3\widehat j$. Another vector that is perpendicular to $\overrightarrow F$ is

The cross product $\hat{i} imes \hat{j}$ is equal to:

The magnitude of the cross product of two vectors of magnitudes 4 and 5 units, with an angle of $30^\circ$ between them, is: