NEET Chemistry MCQ: NCERT Concentration Methods

🎯Difficulty :Hard

⚡ Time Required :1 mins

🔄Ncert Concepts :Biomolecules, Separation Techniques

Related Questions

In the reaction, ${\rm{VO}} + {\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3} o {\rm{FeO}} + {{\rm{V}}_2}{{\rm{O}}_5}{\rm{.}}$ . The eq.wt. of ${{\rm{V}}_2}{{\rm{O}}_5}$ is equal to its :

mol. wt.

$mol.{\rm{ }}wt./8$

$mol.{\rm{ }}wt./6$

None of these

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🎯Difficulty :Easy

⚡ Time Required :3 mins

🔄Ncert Concepts :Equivalent weight, Redox reaction, Oxidation number

In the standardization of ${\rm{N}}{{\rm{a}}_2}{{\rm{S}}_2}{{\rm{O}}_3}$ using ${{\rm{K}}_2}{\rm{C}}{{\rm{r}}_2}{{\rm{O}}_7}$ by iodometry, the equivalent weight of ${{\rm{K}}_2}{\rm{C}}{{\rm{r}}_2}{{\rm{O}}_7}$ is :

$\begin{array}{*{20}{l}}

{\left( {molecular{\rm{ }}weight} \right)/2}

\end{array}$

$\begin{array}{*{20}{l}}

{\left( {molecular{\rm{ }}weight} \right)/6}

\end{array}$

$\begin{array}{*{20}{l}}

{\left( {molecular{\rm{ }}weight} \right)/3}

\end{array}$

Same as molecular weight

Question Tags

🎯Difficulty :Medium

⚡ Time Required :3 mins

🔄Ncert Concepts :Redox Titration, Equivalent Weight, Oxidation Number

In the following change, $3{\rm{Fe}} + 4{{\rm{H}}_2}{\rm{O}} o {\rm{F}}{{\rm{e}}_3}{{\rm{O}}_4} + 4{{\rm{H}}_2}$ . If the atomic weight of iron is 56, then its equivalent weight will be :

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