In the standardization of using by iodometry, the equivalent weight of is :
$\begin{array}{*{20}{l}}
{\left( {molecular{\rm{ }}weight} \right)/2}
\end{array}$
$\begin{array}{*{20}{l}}
{\left( {molecular{\rm{ }}weight} \right)/6}
\end{array}$
$\begin{array}{*{20}{l}}
{\left( {molecular{\rm{ }}weight} \right)/3}
\end{array}$
Same as molecular weight
Related Questions
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0.5 kg
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Molarity
Millimole
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None of these
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