An organic compound is found to contain 40% carbon, 6.67% hydrogen, and 53.33% oxygen by weight. What is the empirical formula of this compound? (Atomic weights: C=12, H=1, O=16)
CH2O
C2H4O2
CHO
CH3O
Related Questions
An organic compound contains 49.3% carbon, 6.84% hydrogen and its vapour density is 73. Molecular formula of compound is
CβHβ Oβ
CβHββOβ
Cβ HββOβ
CβHβOβ
A compound Y contains 16% of element P (atomic mass = 32 u), 4% of element Q (atomic mass = 16 u), and the rest is element R (atomic mass = 12 u). What is the empirical formula of compound Y?
PβQRββ
PQRββ
PβQβRββ
PQβRββ
A substance contains 24% carbon and 76% fluorine by weight. What is the empirical formula of this substance? (Atomic weights: C=12, F=19)
C2F4
CF
CF4
CF2
A mineral sample contains 27.27% of element X (atomic mass = 56 u) and 72.73% of element Y (atomic mass = 16 u). What is the empirical formula of the mineral?
XY3
X2Y3
XY9
X3Y2
Which of the following represents an empirical formula?
CHO
CHO
NO
CHO
A Carbon compound contains 12.8 % Carbon, 2.1 % Hydrogen and 85.1 % of Bromine. The molecular weight of the compound is 187.9. Its molecular formula is (at. Wt. of Br = 80)
A compound has an empirical formula of CH and a molecular mass of 78 g/mol. What is its molecular formula?
C2H2
C4H4
C6H6
C8H8
What is the empirical formula of a compound having 40% carbon, 6.66% hydrogen and 53.34% oxygen?
A compound has the empirical formula C2H4O. If its molecular mass is 88 g/mol, what is its molecular formula?
C2H4O
C3H6O1.5
C4H8O2
C4H8O
Which of the following pairs has the same empirical formula?
C2H6 and C4H12
CH3OH and CH3CH2OH
H2O and H2O2
N2O3 and NO