Consider the following reaction: $xMnO_4^ - + y{C_2}O_4^{2 - } + z{H^ + } o xM{n^{2 + }} + 2yC{O_2} + \frac{z}{2}{H_2}O$

The values of x, y and z in the reaction are, respectively

A compound Y contains 16% of element P (atomic mass = 32 u), 4% of element Q (atomic mass = 16 u), and the rest is element R (atomic mass = 12 u). What is the empirical formula of compound Y?

Which of the following represents an empirical formula?

The formula of a compound which gives simple whole number atomic ratio in one molecule of a compound is called:

Which of the following pairs has the same empirical formula?

A mineral sample contains 27.27% of element X (atomic mass = 56 u) and 72.73% of element Y (atomic mass = 16 u). What is the empirical formula of the mineral?

What is the empirical formula of a compound containing 80% carbon and 20% hydrogen?

An organic compound contains 78% (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1]

An organic compound having molecular mass 60 is found to contain C=20%, H=6.67% and N=46.67% while rest is oxygen. On heating it gives ${\rm{N}}{{\rm{H}}_3}$ along with a solid residue. The solid residue gives violet colour with alkaline copper sulphate solution. The compound is

An organic compound contains 78% (by wt.) carbon and the remaining percentage of hydrogen. What is the empirical formula of this compound? (Atomic wt. of C is 12, H is 1)

If a compound consists of 92.3% carbon and 7.7% hydrogen by weight, what is its empirical formula? (Atomic weights: C = 12, H = 1)