A metal M forms a chloride with the formula MCl$_2$. The equivalent weight of the metal M is 24. What is the molecular weight of its oxide?

In the reaction, ${\rm{C}}{{\rm{r}}_2}{\rm{O}}_7^{2 - } + 14{{\rm{H}}^ + } + 6{{\rm{I}}^ - } o 2{\rm{C}}{{\rm{r}}^{3 + }} + 3{{\rm{H}}_2}{\rm{O}} + 3{{\rm{I}}_2}$, The eq.wt. of ${\rm{C}}{{\rm{r}}^{3 + }}$) is :

Maximum number of atoms are present in

The equivalent weight of an element is 12. What is the weight of the element that combines with 8g of oxygen?

One mole of a gas is defined as:

The equivalent weight of ${\rm{SnC}}{{\rm{l}}_2}$ in the reaction, ${\rm{SnC}}{{\rm{l}}_2} + {\rm{C}}{{\rm{l}}_2} o {\rm{SnC}}{{\rm{l}}_4}$ is :

The eq. wt. of ${{\rm{I}}_2}$ in the change ${{\rm{I}}_2} o {\rm{IO}}_3^ -$ is :

A mixture of $NaHCO_3$ and $Na_2CO_3$ is titrated against $0.5$ N $HCl$ using phenolphthalein as the indicator. $10$ mL of the mixture consumes $4$ mL of $HCl$ to reach the endpoint. Methyl orange is then added to the same solution, and a further $6$ mL of $HCl$ is required to reach the second endpoint. What is the equivalent weight of the mixture?

If the equivalent weight of a metal is 9, what is its valency given its atomic weight is 27?

The molar ratio of ${H_2}{\rm{ }}and{\rm{ }}{O_2}$ gases in a mixture which contains these two gases in mass ratio of 1 : 4 will be

Which has maximum number of atoms ?