Milliequivalent of a solute in a solution can be given by:

Milliequivalent of a solute in a solution can be given by:

The equivalent weight of iron in ${\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3}$ would be :

An element X forms a chloride with the formula XCl$_3$ and another chloride with the formula XCl$_5$. 0.1 moles of XCl$_3$ requires 60 mL of 1 N NaOH for complete hydrolysis, while 0.1 moles of XCl$_5$ requires 100 mL of 1 N NaOH. What is the equivalent weight of the element X in XCl$_3$ and XCl$_5$ respectively?

Equivalent mass of ${\rm{N}}{{\rm{a}}_2}{{\rm{S}}_2}{{\rm{O}}_3}$ in its reaction with ${{\rm{I}}_2}$ is equal to :

Maximum number of atoms are present in

Cerric ammonium sulphate and potassium permanganate are used as oxidising agents in acidic medium for oxidation of ferrous ammonium sulphate to ferric sulphate. The ratio of number of moles of cerric ammonium sulphate required per mole of ferrous ammonium sulphate to the number of moles of ${\rm{KMn}}{{\rm{O}}_4}$ required per mole of ferrous ammonium sulphate, is

In the reaction, ${{\rm{N}}_2} o {\rm{N}}{{\rm{H}}_3}{\rm{.}}$. The eq.wt. of ${{\rm{N}}_2}$ and ${\rm{N}}{{\rm{H}}_3}$ are respectively equal to :

The ratio of amounts of ${{\rm{H}}_2}{\rm{S}}$ needed to precipitate all the metal ions from 100 mL 1M ${\rm{AgN}}{{\rm{O}}_3}$ and 100 mL of 1${\rm{M\;CuS}}{{\rm{O}}_4}$ is :

What is the equivalent weight of oxygen in its normal oxide formation?

56g of CO contains (NA = Avogadro’s No.)