0.1 mol of He

0.2 mol of He

0.1 mol of $H_2$

0.1 mol of $O_2$

M = 10, N = 40

M = 30, N = 20

M = 20, N = 30

M = 40, N = 10

1 mol

0.5 mol

2 mol

18 mol

46.0 u

23.0 u

11.5 u

92.0 u

${\rm{1}}\,\,{\rm{g}}$of ${\rm{Ag}}\,\left( {\rm{s}} \right)$ [ Atomic mass of $Ag = {\rm{ }}108$ ]

${\rm{1}}\,\,{\rm{g}}$ of ${\rm{Mg}}\,\left( {\rm{s}} \right)$ [ Atomic mass of $Mg = {\rm{ }}24$ ]

${\rm{1}}\,\,{\rm{g}}$ of ${{\rm{O}}_{\rm{2}}}\left( {\rm{g}} \right)$ [ Atomic mass of $O = {\rm{ 16}}$ ]

${\rm{1}}\,\,{\rm{g}}$ of ${\rm{Li}}\,\left( {\rm{s}} \right)$ [ Atomic mass of $Li = {\rm{ 7}}$ ]

$6.022 imes 10^{18}$

$3.011 imes 10^{18}$

$1.204 imes 10^{19}$

$6.022 imes 10^{17}$

1 g of Li

1 g of Ag

1 g of Mg

1 g of O2

Twice that in 60 g carbon

$6.023 imes {10^{22}}$

Half in 8 gr of He

$558.5 imes 6.023 imes {10^{23}}$

$16{\rm{g}}{{\rm{O}}_2},14{\rm{g}}{{\rm{N}}_2}$

$8{\rm{g}}{{\rm{O}}_2},22{\rm{g}}{{\rm{N}}_2}$

$28{\rm{g}}{{\rm{N}}_2},22{\rm{g C}}{{\rm{O}}_2}$

$32{\rm{g}}{{\rm{O}}_2},32{\rm{g}}{{\rm{N}}_2}$

28 g CO contains 12 g carbon and 16 g oxygen

One mole of CO reacts completely with half mole of ${O_2}$ to form $C{O_2}$

${N_2}$ and CO have same molar mass

All of these

71.44

80

62.5

90.5