As the bond order between two atoms increases, the bond length generally:
Increases
Decreases
Remains the same
Becomes zero
Related Questions
The electronic structure of four elements A,B,C,D are $\begin{array}{l}
\left( A \right)1{s^2},,,,(B,)1{s^2},2{s^2},2{p^2}\
\left( C \right)1{s^2},2{s^2},2{p^5},,,\left( D \right)1{s^2},2{s^2},2{p^6}
\end{array}$ The tendency to form electrovalent bond is largest in
Which bond has the highest bond energy?
Coordinate bond
Sigma bond
Multiple bond
Polar covalent bond
A larger bond enthalpy indicates a:
Weaker bond
Stronger bond
Longer bond
No bond
The bond order in is equal to bond order in:
Which of the following exhibits diamagnetic behavior:
NO
The bond distance is the longest in
The correct increasing order of polarising power is:
The half of the difference between the number of electrons in bonding molecular orbitals and antibonding molecular orbitals is known as:
Bond order
Proton order
Molecular order
Electron order
The decreasing order of bond angle is
$\begin{array}{*{20}{l}}
{{\rm{N}}{{\rm{O}}_2} > {\rm{NO}}_2^ + > {\rm{NO}}_2^ - }
\end{array}$
The electronic structure of four elements A,B,C,D are $\begin{array}{l}
\left( A \right)1{s^2},,,,(B,)1{s^2},2{s^2},2{p^2}\
\left( C \right)1{s^2},2{s^2},2{p^5},,,\left( D \right)1{s^2},2{s^2},2{p^6}
\end{array}$ The tendency to form electrovalent bond is largest in