Which of the following statements regarding the hybridization of [Ni(CN)4]2- and [NiCl4]2- is INCORRECT?
[Ni(CN)4]2- is square planar and diamagnetic
[NiCl4]2- is tetrahedral and paramagnetic
[Ni(CN)4]2- is dsp2 hybridized
[Ni(CN)4]2- is paramagnetic
Related Questions
How many hybrid orbitals are formed in hybridization?
5
4
3
6
A molecule which cannot exist theoretically is:
The geometry and magnetic behavior of the complex are:
square planar, paramagnetic
tetrahedral, diamagnetic
square planar, diamagnetic
tetrahedral, paramagnetic
Which type of hybridization occurs in methane ()?
What is the hybridization and magnetic property of ?
, diamagnetic
, paramagnetic
, paramagnetic
, diamagnetic
Which of the following statements is true regarding ?
It is diamagnetic and inner orbital complex
It is diamagnetic and outer orbital complex
It is paramagnetic and inner orbital complex
It is paramagnetic and outer orbital complex
The molecule exhibits a trigonal bipyramidal geometry. According to Valence Bond Theory, what type of hybridization does the phosphorus atom undergo, and how does this hybridization explain the observed bond angles?
hybridization, resulting in bond angles of .
hybridization, resulting in bond angles of and .
hybridization, resulting in bond angles of .
hybridization, resulting in bond angles of .
The bond angle in a molecule with hybridization is closest to:
According to VBT, the number of covalent bonds an atom can form is equal to:
The number of unpaired electrons
The number of paired electrons
The total number of electrons
The number of protons
A covalent bond is formed between the atoms by the overlapping of orbitals containing:
Single electron
Paired electron
Single electron with parallel spin
Single electron with opposite spin