A mixture of nitrogen and oxygen gases exerts a total pressure of 1.2 atm. If the partial pressure of nitrogen is 0.8 atm, what is the partial pressure of oxygen according to Dalton's Law?
0.4 atm
1.2 atm
2.0 atm
0.8 atm
Related Questions
Two gases, (1 mole) and (0.5 moles), are mixed in a 2-litre vessel at a temperature of 273 K. Using the ideal gas constant , find the total pressure (in atm) exerted by the mixture.
17 atm
34 atm
8.5 atm
25 atm
A mixture of and gases in a cylinder contains of and of . If the total pressure of the mixture of the gases in the cylinder is bar, the partial pressure of is :
[Use atomic masses ]
bar
bar
bar
bar
10g each of , , and are mixed in a container of volume 'V' at 27Β°C. What is the total pressure exerted by the mixture? (Assume ideal gas behavior. Atomic masses: =4, =20, =40, R= 0.0821 L atm/mol K)
atm
atm
atm
atm
The partial pressure of a dry gas is:
Less than that of wet gas
Greater than that of wet gas
Equal to that of wet gas
None of the above
A mixture of gases contains 4 moles of , 2 moles of , and 1 mole of at a total pressure of 2 atm. What is the mole fraction of and its partial pressure?
0.143, 0.286 atm
0.286, 0.571 atm
0.429, 0.857 atm
0.571, 1.142 atm
A container of volume 500 mL holds a mixture of 2 g of and 1 g of at . What is the total pressure (in atm) inside the container? (Use )
13.84
27.675
41.51
55.35
If density of a gas in closed cylinder is at 4.1 atm pressure and temperature then molar mass of the gas will be
A container holds a mixture of and gases. The partial pressure of is 0.3 atm, and its mole fraction is 0.6. If 0.2 moles of is added to the mixture while keeping the temperature and volume constant, what will be the total pressure of the resulting mixture?
0.7 atm
0.6 atm
0.8 atm
0.9 atm
Two gases and having the mole ratio of in a container, exert a pressure of 8 atm. If is removed, what would be the pressure due to only, temperature remaining constant?