NEET Chemistry Coordination Compounds MCQs

Which of the following compounds exhibits both optical and geometrical isomerism?

An organic compound with molecular formula $C_6H_{10}$ exhibits optical isomerism and decolorizes bromine water. It does not show geometrical isomerism. Which of the following could be the compound?

Which of the following compounds exhibits geometrical isomerism?

Which of the following compounds exhibits both geometrical and optical isomerism?

Compounds having the same molecular formula but different arrangements of atoms or groups on either side of a double bond or ring are called:

Which one of the following octahedral complexes will not show geometrical isomerism? (A and B are monodentate ligands)

$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_4}{{\left( {{\rm{N}}{{\rm{O}}_2}} \right)}_2}} \right]{\rm{Cl}}$ exhibits:

For the given complex ${\left[ {{\rm{CoC}}{{\rm{l}}_2}\left( {{\rm{en}}} \right){{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_2}} \right]^ + },$ the number of geometrical isomers, the number of optical isomers and total number of isomers of all type possible respectively are

The type of isomerism shown by the complex $\left[ {{\rm{Co}}\,{\rm{C}}{{\rm{l}}_{\rm{2}}}\,{{\left( {{\rm{en}}} \right)}_{\rm{2}}}} \right]$ is

The existence of two different coloured complexes with the composition of ${\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_4}{\rm{C}}{{\rm{l}}_2}} \right]^ + }$ is due to: