The Question is from neet-chemistry general-principles-and-processes-of-isolation-of-e extraction-of-crude-metal, and it was created by the author Mr. S M HUSSAIN

Question

A sulphide ore of metal M is roasted to produce a mixture of metal oxide and metal sulphate.  Leaching this mixture with dilute $H_2SO_4$ selectively dissolves the sulphate, leaving the oxide behind. Which combination of properties of M is MOST LIKELY responsible for this behaviour?

Mr. S M HUSSAIN · Accepted Answer

## CORE INFORMATION
✓ **Answer**: [Option A]
## CONCEPT FRAMEWORK
	**Primary Concept**: Solubility of compounds in acid
	**Related Topics**: Metal extraction, Roasting of ores, Leaching techniques
	**Prerequisites**: Basic understanding of acid-base chemistry and metal properties
## SOLUTION PATHWAY
**Given Information**:
		- Metal M is present as a sulphide ore.
		- The roasting process produces a mixture of metal oxide and metal sulphate.
		- Leaching is performed using dilute $H_2SO_4$.
**Method & Steps**:
	1. Identify the solubility of the compounds produced.
		Reasoning: The goal is to dissolve as much of the sulphate as possible while leaving the oxide behind.
		Formula/Rule: Solubility product principle.
	2. Analyze the solubility of the oxide and sulphate of metal M.
		Working: For selective leaching, the sulphate must be significantly more soluble in dilute acid than the oxide.
		Key Point: A stable oxide will resist dissolution in dilute acid.
	3. Conclude on the properties required for M.
		Result: M must form a sulphate that is more soluble than its oxide, and the oxide must be stable in dilute acid.
		Verification: This matches with the behavior described in the question.
## OPTION ANALYSIS
[A] ✓: M forms a sulphate that is significantly more soluble than its oxide, and the oxide is relatively stable in dilute acid. This allows for selective leaching of the sulphate.
[B] :x: M forms a sulphide that is easily roasted, and the resulting sulphate is insoluble in dilute acid. This contradicts the requirement for selective dissolution.
[C] :x: M forms an oxide and a sulphate that are both readily soluble in dilute acid, but the sulphide is resistant to roasting. This would not allow for selective behavior as both would dissolve.
[D] :x: M forms an oxide that is more soluble than its sulphate, and the sulphide is easily converted to the oxide during roasting. This would result in the oxide also being dissolved during leaching.
## LEARNING AIDS
	**Common Mistakes**:
		1. Confusing solubility properties: Ensure to compare solubility of both the sulphate and oxide carefully.
		2. Misunderstanding roasting results: Remember that roasting changes the form of the metal, affecting solubility.
	**Quick Tips**:
		1. Use the solubility rules for common sulphates and oxides to quickly assess likely outcomes.
		2. Remember that stability in acid often relates to the electronegativity and bonding type in the compound.

Mr. S M HUSSAIN · Answer

The correct Option is "M forms a sulphate that is significantly more soluble than its oxide, and the oxide is relatively stable in dilute acid."

Mr. S M HUSSAIN · Answer

M forms a sulphide that is easily roasted, and the resulting sulphate is insoluble in dilute acid.

Mr. S M HUSSAIN · Answer

M forms an oxide and a sulphate that are both readily soluble in dilute acid, but the sulphide is resistant to roasting.

Mr. S M HUSSAIN · Answer

M forms an oxide that is more soluble than its sulphate, and the sulphide is easily converted to the oxide during roasting.

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