Given $heta$ is the angle between ${\rm{\vec A}}\,and\,{\rm{\vec B}}$. Then $\left| {\hat A imes \hat B\;} \right|$ is equal to

A vector $\overrightarrow {{{\rm{F}}_1}}$ is along the positive Y-axis. If its vector product with another vector $\overrightarrow {{{\rm{F}}_1}}$ is zero, then $\overrightarrow {{{\rm{F}}_2}}$ could be

The area of parallelogram formed from the vectors ${\rm{\vec A}} = \hat i - 2\hat j + 3\hat k\,and\,{\rm{\vec B}} = 3\hat i - 2\hat j + \hat k$ as adjacent sides is

If vectors $\overrightarrow A$ and $\overrightarrow B$ are $3\widehat i - 4\widehat j + 5\widehat k$ and $2\widehat i + 3\widehat j - 4\widehat k$ respectively, then find the unit vector parallel to $\overrightarrow A + \overrightarrow B$

What is the unit vector along $\hat i + \hat j\,\,?$

Two vectors $\vec{A}$ and $\vec{B}$ have equal magnitudes. Under what condition will their difference have the same magnitude as either of the vectors?

The magnitudes of the two vectors ${\rm{\vec a}}\,and\,{\rm{\vec b}}$ are a and b respectively. The vector product of ${\rm{\vec a}}\,and\,{\rm{\vec b}}$ cannot be

The magnitude of the vectors product o two vectors is $\sqrt 3$ times their scalar product. The angle between the two vectors is

The position vector of a particle is given by $\vec{r} = (3t^2 - 2t)\hat{i} - (t^3)\hat{j}$. The velocity of the particle at $t=2$ s is perpendicular to:

The magnitude of the vectors product o two vectors is $\sqrt 3$ times their scalar product. The angle between the two vectors is

A vector $\u{A}$ has magnitude 5 units and is directed along the positive x-axis. Another vector $\u{B}$ has magnitude 3 units and is directed along the negative y-axis. What is the magnitude of the vector $\u{A} - \u{B}$?