Two forces, each of magnitude F, have a resultant of the same magnitude F. The angle between the two forces is

The velocity of a body at time t=0 is $10\sqrt 2 \;m/s$ in the north-east direction and it is moving with an acceleration of $2\;m/{s^2}$ directed towards the south. The magnitude and direction of the velocity of the body after 5 sec will be

Two vectors ${\rm{\vec A}}\,and\,{\rm{\vec B}}$ are inclined at an angle $heta$. Now if the vectors are interchanged then the resultant turns through an angle $\beta$. Which of the following relation is true

The wind appears to blow from the north to a man moving in the north-east direction. When he doubles his velocity the wind appears to move in the direction ${\cot ^{ - 1}}\left( 2 \right)$ east of north. The actual direction of the wind is

The resultant of two forces at right angle is 5N. When the angle between them is ${120^0}$, the resultant is $\sqrt {13}$. Then the force are

The velocity of a body at time t=0 is $10\sqrt 2 \;m/s$ in the north-east direction and it is moving with an acceleration of $2\;m/{s^2}$ directed towards the south. The magnitude and direction of the velocity of the body after 5 sec will be

A body of weight 10 N is suspended by two strings making angles of $30^\circ$ and $60^\circ$ with the horizontal. The tension in the string at $30^\circ$ is:

Two forces of equal magnitude act on a particle. If the angle between them is 60 degrees, what is the ratio of the magnitude of their resultant to the magnitude of either force?

Which law states that if a number of forces acting at a point can be represented in magnitude and direction by the sides of a polygon taken in order, then the forces are in equilibrium?

Given ${\rm{\vec R}} = {\rm{\vec A}} + {\rm{\vec B}}\,$ and R=A=B. The angle between ${\rm{\vec A\;and}}\overrightarrow {{\rm{\;B}}}$ is

Two forces of 3 N and 4 N act at a point at right angles to each other. The magnitude of their resultant is: