The Question is from neet-chemistry nitrogen-compounds , and it was created by the author Mr. S M HUSSAIN

Question

A novel polysaccharide is discovered containing only glucose monomers.  Upon partial hydrolysis, it yields a mixture of maltose and isomaltose. What glycosidic linkages are MOST likely present in the original polysaccharide?

Mr. S M HUSSAIN · Accepted Answer

## CORE INFORMATION
✓ **Answer**: C
## CONCEPT FRAMEWORK
 **Primary Concept**: Carbohydrate structure and hydrolysis
 **Related Topics**: Glycosidic linkages, disaccharides, polysaccharides
 **Prerequisites**: Understanding of α and β glycosidic bonds, maltose and isomaltose structures.
## SOLUTION PATHWAY
**Given Information**:
	* Polysaccharide composed only of glucose monomers.
	* Partial hydrolysis yields maltose and isomaltose.
**Method & Steps**:
	1. **Analyze the products of hydrolysis:** Maltose is a disaccharide formed by an α-1,4-glycosidic linkage between two glucose molecules. Isomaltose is a disaccharide formed by an α-1,6-glycosidic linkage between two glucose molecules.
		Reasoning: Since both maltose and isomaltose are produced, the original polysaccharide must contain both types of linkages.
		Formula/Rule: Hydrolysis breaks glycosidic bonds.
	2. **Deduce the original polysaccharide structure:** The presence of both maltose and isomaltose indicates that the original polysaccharide contains both α-1,4 and α-1,6 glycosidic linkages.
		Working: The partial hydrolysis breaks some, but not all, of the glycosidic bonds.  The resulting mixture contains both α-1,4 and α-1,6 linked disaccharides, implying the presence of both types of linkages in the original polysaccharide.
		Key Point: Partial hydrolysis does not necessarily break all linkages.  It can result in a mixture of smaller polysaccharides and disaccharides.
	3. **Identify the most likely linkage type:**  The most likely structure is one containing both α-1,4 and α-1,6 glycosidic linkages.
		Result: Both α-1,4 and α-1,6 glycosidic linkages.
		Verification: The presence of both maltose and isomaltose as hydrolysis products strongly supports this conclusion.
## OPTION ANALYSIS
A :x: Only α-1,4 linkages would only produce maltose upon hydrolysis.
B :x: β-linkages are not consistent with the production of maltose and isomaltose.
 C ✓: Both α-1,4 and α-1,6 linkages are consistent with the production of both maltose and isomaltose upon partial hydrolysis.
D :x: β-linkages are not consistent with the production of maltose and isomaltose.
## LEARNING AIDS
 **Common Mistakes**:
		1.Assuming complete hydrolysis:  Partial hydrolysis yields fragments; complete hydrolysis would yield only monomers.
			How to avoid: Carefully read the question; understand the difference between partial and complete hydrolysis.
		2.Confusing α and β linkages:  α and β linkages have different sterochemistry and yield different products.
			How to avoid: Revise the structures of α and β glycosidic bonds and their related disaccharides.
 **Quick Tips**:
		1.Remember the structures of common disaccharides (maltose, isomaltose, cellobiose, etc.).
		2.Focus on the products of hydrolysis to deduce the linkages present in the original polysaccharide.

Mr. S M HUSSAIN · Answer

Only α-1,4

Mr. S M HUSSAIN · Answer

Only β-1,4

Mr. S M HUSSAIN · Answer

The correct Option is "Both α-1,4 and α-1,6"

Mr. S M HUSSAIN · Answer

Both β-1,4 and β-1,6

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