1.

    The maximum bond energy is present

    A

    C−H{\rm{C}} - {\rm{H}}

    B

    C−C{\rm{C}} - {\rm{C}}

    C

    C−N{\rm{C}} - {\rm{N}}

    D

    C−O{\rm{C}} - {\rm{O}}

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Understanding
    🎯Difficulty :Easy
    ⚡ Time Required :2 mins
    🔄Ncert Concepts :bond energy, bond strength, electronegativity, atomic size

    Related Questions

    1.

    Which of the following molecules represents the order of hybridization from left to right atoms ?

    A

    CH3 − CH = CH− CH3{\rm{C}}{{\rm{H}}_{\rm{3}}}\,{\rm{ - }}\,{\rm{CH}}\,{\rm{ = }}\,{\rm{CH - }}\,{\rm{C}}{{\rm{H}}_{\rm{3}}}

    B

    HC = C − C = CH{\rm{HC}}\,{\rm{ = }}\,{\rm{C}}\,{\rm{ - }}\,{\rm{C}}\,{\rm{ = }}\,{\rm{CH}}

    C

    CH2 =  CH − CH = CH2{\rm{C}}{{\rm{H}}_{\rm{2}}}\,{\rm{ = }}\,\,{\rm{CH}}\,{\rm{ - }}\,{\rm{CH}}\,{\rm{ = }}\,{\rm{C}}{{\rm{H}}_{\rm{2}}}

    D

     CH2 = CH − C = CH\,{\rm{C}}{{\rm{H}}_{\rm{2}}}\,{\rm{ = }}\,{\rm{CH}}\,{\rm{ - }}\,{\rm{C}}\,{\rm{ = }}\,{\rm{CH}}

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Analyzing
    🎯Difficulty :Easy
    ⚡ Time Required :3 mins
    🔄Ncert Concepts :Hybridization, Sigma bonds, Pi bonds, Molecular structure

    2.

    Considering the state of hybridization of carbon atoms, find out the molecule among the following which is linear?

    A

    CH3−CH2−CH2−CH3{\rm{C}}{{\rm{H}}_3}-{\rm{C}}{{\rm{H}}_2}-{\rm{C}}{{\rm{H}}_2}-{\rm{C}}{{\rm{H}}_3}

    B

    CH3−CH=CH−CH3{\rm{C}}{{\rm{H}}_3}-{\rm{CH}} = {\rm{CH}}-{\rm{C}}{{\rm{H}}_3}

    C

    CH3−C≡C−CH3{\rm{C}}{{\rm{H}}_3}-{\rm{C}} \equiv {\rm{C}}-{\rm{C}}{{\rm{H}}_3}

    D

    CH2=CH−CH2−C≡CH{\rm{C}}{{\rm{H}}_2} = {\rm{CH}}-{\rm{C}}{{\rm{H}}_2}-{\rm{C}} \equiv {\rm{CH}}

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Analyzing
    🎯Difficulty :Easy
    ⚡ Time Required :3 mins
    🔄Ncert Concepts :hybridization, molecular geometry, linear molecule

    3.

    pent−2−en−4−yne{\rm{pent -2 - en - 4 - yne}} is

    A

    10 σ  bonds  and  3π bonds{\rm{10}}\,{\rm{\sigma }}\,\,{\rm{bonds}}\,\,{\rm{and}}\,\,{\rm{3\pi }}\,{\rm{bonds}}

    B

    8 σ  bonds  and  5π  bonds8\,{\rm{\sigma }}\,\,{\rm{bonds}}\,\,{\rm{and}}\,\,5{\rm{\pi }}\,\,{\rm{bonds}}

    C

    11 σ  bonds  and  2π  bonds11\,{\rm{\sigma }}\,\,{\rm{bonds}}\,\,{\rm{and}}\,\,2{\rm{\pi }}\,\,{\rm{bonds}}

    D

    13 σ  bonds  and  noπ  bonds13\,{\rm{\sigma }}\,\,{\rm{bonds}}\,\,{\rm{and}}\,\,{\rm{no \pi }}\,\,{\rm{bonds}}

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Application
    🎯Difficulty :Easy
    ⚡ Time Required :3 mins
    🔄Ncert Concepts :Organic Nomenclature, Sigma Bonds, Pi Bonds, Structural Formulas

    4.

    The number of sp3s{p^3}- hybrid carbons in 2-butyne is :

    A

    4

    B

    3

    C

    2

    D

    1

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Application
    🎯Difficulty :Medium
    ⚡ Time Required :2 mins
    🔄Ncert Concepts :Hybridization, Organic Nomenclature, Molecular Structure

    5.

    The hybridisation of carbon atoms in C−CC - C single bond of H−C≡C−CH=CH2H - C \equiv C - CH = C{H_2}

    A

    SP3−SP3S{P^3} - S{P^3}

    B

    SP2−SPS{P^2} - SP

    C

    SP−SP2SP - S{P^2}

    D

    SP3−SPS{P^3} - SP

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Application
    🎯Difficulty :Easy
    ⚡ Time Required :2 mins
    🔄Ncert Concepts :hybridization, sigma bonds, pi bonds, molecular structure

    6.

    The structure of tertiary butyl carbonium ion is :

    A

    Pyramidal

    B

    Trigonal planar

    C

    Tetrahedral

    D

    Square planar

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Understanding
    🎯Difficulty :Easy
    ⚡ Time Required :2 mins
    🔄Ncert Concepts :carbocation structure, VSEPR theory, hybridization

    7.

    When the hybridization state of a carbon atom changes from sp3s{p^3} to sp2s{p^2} and finally to spsp, the angle between the hybridized orbitals :

    A

    Is not affected

    B

    Increases progressively

    C

    Decreases considerably

    D

    Decreases gradually

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Understanding
    🎯Difficulty :Easy
    ⚡ Time Required :2 mins
    🔄Ncert Concepts :hybridization, bond angle

    8.

    Overlap of which of the following atomic orbitals would be maximum to form the strongest covalent bond?

    A

    1s−2s(σ)1s - 2s\left( \sigma \right)

    B

    1s−2p(σ)1s - 2p\left( \sigma \right)

    C

    2p−2p(π)2p - 2p\left( \pi \right)

    D

    2p−2p(σ)2p - 2p\left( \sigma \right)

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Analyzing
    🎯Difficulty :Easy
    ⚡ Time Required :2 mins
    🔄Ncert Concepts :atomic orbitals, covalent bond, sigma bond, pi bond, orbital overlap, bond strength

    9.

    The compound in which carbon uses only its sp3s{p^3} hybrid orbitals for bond formation is

    A

    (CH3)3COH{\left( {{\rm{C}}{{\rm{H}}_3}} \right)_3}{\rm{COH}}

    B

    HCOOH{\rm{HCOOH}}

    C

    CH3CHO{\rm{C}}{{\rm{H}}_3}{\rm{CHO}}

    D

    (H2N)2CO{\left( {{{\rm{H}}_2}{\rm{N}}} \right)_2}{\rm{CO}}

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Analyzing
    🎯Difficulty :Easy
    ⚡ Time Required :3 mins
    🔄Ncert Concepts :hybridization, sigma bonds, pi bonds, molecular structure

    10.

    Glycerine contains

    A

    1∘^ \circ carbon

    B

    2∘^ \circ carbon

    C

    3∘^ \circ carbon

    D

    Both 1∘^ \circ and 2∘^ \circ carbon

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:Organic Chemistry: Some basic principles and techniques
    🎯Topic:Hybridisation
    🎓 Ncert Level:Understanding
    🎯Difficulty :Easy
    ⚡ Time Required :2 mins
    🔄Ncert Concepts :Organic Chemistry, Carbon Classification, Glycerol Structure

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