1.

    The observed freezing point depression of a 0.01 m aqueous solution of a weak acid HA is 0.0205 °C. If the KfK_f of water is 1.86 K kg/mol, which expression correctly calculates the percent ionization of the weak acid?

    A

    (0.0205/1.86/0.01)1(21)imes100 \frac{(0.0205/1.86/0.01) - 1}{(2-1)} imes 100

    B

    (1.86imes0.01/0.0205)1(21)imes100 \frac{(1.86 imes 0.01/0.0205) - 1}{(2-1)} imes 100

    C

    (0.0205/1.86/0.01)(21)imes100 \frac{(0.0205/1.86/0.01)}{(2-1)} imes 100

    D

    (1.86imes0.01imes0.0205)(21)imes100 \frac{(1.86 imes 0.01 imes 0.0205)}{(2-1)} imes 100

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    Related Questions

    1.

    Colligative properties depend on:

    A

    The nature of the solute particles

    B

    The size of the solute particles

    C

    The number of solute particles in the solution

    D

    The charge of the solute particles

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    2.

    Molal elevation constant of a liquid is :

    A

    The elevent in b.p. which would be produced by dissolving one mole of solute in 100 g of solvent

    B

    The elevation of b.p. which would be produced by dissolving 1 mole solute in 10 g of solvent.

    C

    Elevation in b.p. which would be produced by dissolving 1 mole of solute in 1000 g of solvent

    D

    None of the above

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    7.

    Vapour pressure of a solvent containing non-volatile solute is :

    A

    More than the vapour pressure of a solvent

    B

    Less than the vapour pressure of solvent

    C

    Equal to the vapour pressure of solvent

    D

    None of the above

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