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At a given temperature, the vapour pressure of pure liquid A is 300 mmHg and that of pure liquid B is 500 mmHg. A solution of A and B shows a total vapour pressure of 400 mmHg. Assuming ideal behavior, what is the mole fraction of A in the liquid phase?
0.2
0.5
0.8
1.0
A solution of glucose (C6H12O6) is prepared by dissolving 18g of glucose in 90g of water at 300K. If the vapour pressure of pure water at 300K is 31.82 mm Hg, what is the vapour pressure of the solution?
31.19 mm Hg
31.82 mm Hg
30.55 mm Hg
32.45 mm Hg
Henry's law constant for CO2 in water at 298 K is Pa. Calculate the mass of CO2 that can be dissolved in 500 mL of water at 298 K and a CO2 partial pressure of 2.5 atm.
0.92 g
1.85 g
3.70 g
0.46 g
The vapour pressure of a pure liquid A is 70 mm Hg at 300 K. When a non-volatile solute B is added to A, the vapour pressure of the solution becomes 63 mm Hg. What is the mole fraction of B in the solution?
0.9
0.1
0.7
0.3
The relative lowering of vapour pressure of a solution containing a non-volatile solute is 0.0125. What is the mole fraction of the solute?
0.0250
0.0125
0.9875
1.0125
18g glucose is added to 178.2 g water. The vapor pressure of water (in torr) for this aqueous solution is.