1.

    A crystal structure has a face-centered cubic (FCC) arrangement of atoms A and atoms B occupy all the octahedral voids. If the atoms A are removed, what is the resulting lattice type for atoms B?

    A

    Simple Cubic

    B

    Body-centered Cubic

    C

    FCC

    D

    Hexagonal Close Packed

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:The Solid State
    🎯Topic:Crystal Systems
    🎓 Ncert Level:Analyzing
    🎯Difficulty :Hard
    ⚡ Time Required :2 mins
    🔄Ncert Concepts :Crystal Systems, Unit Cell, Voids, FCC

    Related Questions

    1.

    The edge of unit cell of fcc Xe crystal is 620 pm. The radius of Xe atom is

    A

    189.37pm189.37{\rm{ }}pm

    B

    209.87pm209.87{\rm{ }}pm

    C

    219.25pm219.25{\rm{ }}pm

    D

    235.16pm235.16{\rm{ }}pm

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:The Solid State
    🎯Topic:Crystal Systems
    🎓 Ncert Level:Application
    🎯Difficulty :Medium
    ⚡ Time Required :2 mins
    🔄Ncert Concepts :Face-centered cubic (fcc) unit cell, relationship between edge length and atomic radius

    2.

    The edge of unit cell of fcc Xe crystal is 620 pm. The radius of Xe atom is

    A

    189.37pm189.37{\rm{ }}pm

    B

    209.87pm209.87{\rm{ }}pm

    C

    219.25pm219.25{\rm{ }}pm

    D

    235.16pm235.16{\rm{ }}pm

    Question Tags
    📚 Subject:Chemistry
    📑 Chapter:The Solid State
    🎯Topic:Crystal Systems
    🎓 Ncert Level:Application
    🎯Difficulty :Medium
    ⚡ Time Required :2 mins
    🔄Ncert Concepts :Face-centered cubic (fcc) unit cell, atomic radius, unit cell edge length

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