The ratio of the wavelengths of the first line of the Lyman series and the first line of the Balmer series in the hydrogen spectrum is:

In hydrogen atom, if the difference in the energy of the electron in $n = 2$ and $n = 3$ orbits is $E$, the ionization energy of hydrogen atom is

Electron in hydrogen atom first jumps from third excited state to second excited state and then from second excited to the first excited state. The ratio of the wavelengths ${\lambda _1}:{\lambda _2}$ emitted in the two cases is

The energy of a hydrogen atom in its ground state is $- 13.6\,\,eV$. The energy of the level corresponding to the quantum number $n = 2$ (first excited state) in the hydrogen atom is

In hydrogen atom, if the difference in the energy of the electron in $n = 2$ and $n = 3$ orbits is $E$, the ionization energy of hydrogen atom is