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In the Bohr model, the ratio of the kinetic energy (K) to the potential energy (U) of an electron in the nth orbit is:
1/2
-1/2
1
-1
In Rutherford's experiment, alpha particles with kinetic energy 'K' were scattered by a gold foil. If the kinetic energy of the alpha particles is quadrupled, how does the distance of closest approach () change?
(1) doubles
(2) becomes one-fourth
(3) becomes one-half
(4) remains the same
Consider an alpha particle approaching a nucleus with an impact parameter . If the speed of the alpha particle is doubled while keeping the impact parameter constant, the distance of closest approach will:
Become one-half.
Remain the same.
Become double.
Become one-fourth.
If the distance of closest approach of an alpha particle to a nucleus is , which quantity significantly increases when the kinetic energy of the incident alpha particle is doubled?
Distance of closest approach
Speed of the alpha particle
Impact parameter
Scattering angle
The distance of closest approach of an alpha particle to a nucleus in Rutherfordโs scattering experiment is . If the kinetic energy of the alpha particle is doubled, the distance of closest approach will be:
r/2
r/4
2r
4r
The ratio of kinetic energy (K) to the potential energy (U) of an electron in a Bohr orbit of the hydrogen atom is:
1/2
-1/2
1
-1
The potential energy of an electron in a particular Bohr orbit is -2E. What is its kinetic energy?
-E
2E
-2E
E
Which of the following correctly relates the kinetic energy (K), potential energy (U), and total energy (E) of an electron in a Bohr orbit?
K = U/2
K = -U
K = U
K = -U/2
In a Bohr orbit, the magnitude of the potential energy of an electron is twice its kinetic energy. If the total energy is -13.6 eV, what is the potential energy?
13.6 eV
-13.6 eV
27.2 eV
-27.2 eV