NEET Physics Atoms MCQs

⚡ Time Required :2 mins

🔄Ncert Concepts :Bohr's model, reduced mass, ionization energy

2.

Consider a muonic atom where a muon (mass $\approx 207 m_e$ ) orbits a proton. What is the ratio of the radius of the first Bohr orbit of this muonic atom to the radius of the first Bohr orbit of a hydrogen atom?

A

1/207

B

207

C

1

D

1/270

Question Tags

🔄Ncert Concepts :Bohr's Model, Muonic Atom, Reduced Mass

3.

A diatomic molecule is made of two masses ${m_1}$ and ${m_2}$ which are separated by a distance $r$ . If we calculate its rotational energy by applying Bohr’s rule of angular momentum quantization, its energy will be given by ( $n$ is an integer)

A

$\frac{{{{\left( {{m_1} + {m_2}} \right)}^2}{n^2}{h^2}}}{{2\,m_1^2\,m_2^2{r^2}}}$

B

$\frac{{{n^2}{h^2}}}{{2\left( {{m_1} + {m_2}} \right){r^2}}}$

C

$\frac{{2\,{n^2}{h^2}}}{{\left( {{m_1} + {m_2}} \right){r^2}}}$

D

$\frac{{{{\left( {{m_1} + {m_2}} \right)}^{}}{n^2}{h^2}}}{{2\,{m_1}\,{m_2}{r^2}}}$

Question Tags

🔄Ncert Concepts :Reduced mass, Rotational energy, Bohr's quantization rule, Angular momentum

4.

A diatomic molecule is made of two masses ${m_1}$ and ${m_2}$ which are separated by a distance $r$ . If we calculate its rotational energy by applying Bohr’s rule of angular momentum quantization, its energy will be given by ( $n$ is an integer)

A

$\frac{{{{\left( {{m_1} + {m_2}} \right)}^2}{n^2}{h^2}}}{{2\,m_1^2\,m_2^2{r^2}}}$

B

$\frac{{{n^2}{h^2}}}{{2\left( {{m_1} + {m_2}} \right){r^2}}}$

C

$\frac{{2\,{n^2}{h^2}}}{{\left( {{m_1} + {m_2}} \right){r^2}}}$

D

$\frac{{{{\left( {{m_1} + {m_2}} \right)}^{}}{n^2}{h^2}}}{{2\,{m_1}\,{m_2}{r^2}}}$

Question Tags

🔄Ncert Concepts :Reduced Mass, Rotational Energy, Bohr's Quantization Rule, Angular Momentum

5.

A diatomic molecule is made of two masses ${m_1}$ and ${m_2}$ which are separated by a distance $r$ . If we calculate its rotational energy by applying Bohr’s rule of angular momentum quantization, its energy will be given by ( $n$ is an integer)

A

\frac{n^2 \hbar^2 (m_1 + m_2)}{2m_1 m_2 r^2}

B

\frac{n\hbar (m_1 + m_2)}{2m_1 m_2 r^2}

C

\frac{n^2 \hbar^2}{2m_1 m_2 r}

D

\frac{n \hbar}{2(m_1+m_2)r^2}

Question Tags

🔄Ncert Concepts :Reduced mass, Rotational energy, Bohr's quantization rule, Angular momentum

6.

A diatomic molecule is made of two masses ${m_1}$ and ${m_2}$ which are separated by a distance $r$ . If we calculate its rotational energy by applying Bohr’s rule of angular momentum quantization, its energy will be given by ( $n$ is an integer)

A

$\frac{{{{\left( {{m_1} + {m_2}} \right)}^2}{n^2}{h^2}}}{{2\,m_1^2\,m_2^2{r^2}}}$

B

$\frac{{{n^2}{h^2}}}{{2\left( {{m_1} + {m_2}} \right){r^2}}}$

C

$\frac{{2\,{n^2}{h^2}}}{{\left( {{m_1} + {m_2}} \right){r^2}}}$

D

$\frac{{{{\left( {{m_1} + {m_2}} \right)}^{}}{n^2}{h^2}}}{{2\,{m_1}\,{m_2}{r^2}}}$

Question Tags

🔄Ncert Concepts :Reduced mass, Moment of inertia, Angular momentum quantization, Rotational kinetic energy

7.

In a hypothetical Bohr hydrogen, the mass of the electron is doubled. The energy ${E_0}$ and the radius ${r_0}$ of the first orbit will be ( ${a_0}$ is the Bohr radius)

A

${E_0} = - 27.2\,\,eV;\,\,{r_0} = {a_0}/2$

B

${E_0} = - 27.2\,\,eV;\,\,{r_0} = {a_0}$

C

${E_0} = - 13.6\,\,eV;\,\,{r_0} = {a_0}/2$

D

${E_0} = - 13.6\,\,eV;\,\,{r_0} = {a_0}$

Question Tags

🎯Difficulty :Medium

🔄Ncert Concepts :Bohr model, energy levels, radius of orbit, reduced mass

8.

In a hypothetical Bohr hydrogen, the mass of the electron is doubled. The energy ${E_0}$ and the radius ${r_0}$ of the first orbit will be ( ${a_0}$ is the Bohr radius)

A

${E_0} = - 27.2\,\,eV;\,\,{r_0} = {a_0}/2$

B

${E_0} = - 27.2\,\,eV;\,\,{r_0} = {a_0}$

C

${E_0} = - 13.6\,\,eV;\,\,{r_0} = {a_0}/2$

D

${E_0} = - 13.6\,\,eV;\,\,{r_0} = {a_0}$

Question Tags

🎯Difficulty :Medium

🔄Ncert Concepts :Bohr model, energy levels, radius of orbit, reduced mass

9.

In a hypothetical Bohr hydrogen, the mass of the electron is doubled. The energy ${E_0}$ and the radius ${r_0}$ of the first orbit will be ( ${a_0}$ is the Bohr radius)

A

${E_0} = - 27.2\,\,eV;\,\,{r_0} = {a_0}/2$

B

${E_0} = - 27.2\,\,eV;\,\,{r_0} = {a_0}$

C

${E_0} = - 13.6\,\,eV;\,\,{r_0} = {a_0}/2$

D

${E_0} = - 13.6\,\,eV;\,\,{r_0} = {a_0}$

Question Tags

🎯Difficulty :Medium