A potentiometer wire of length L and resistance R is connected to a driver cell of negligible internal resistance and emf E. A cell of emf E/2 is balanced at a length L/2. If the length of the potentiometer wire is doubled, at what length will the same cell be balanced?

In a potentiometer, the null points are received at ${\rm{7}}{{\mkern 1mu} ^{{\rm{th}}}}$ wire. If now we have to change the null points at ${\rm{9}}{{\mkern 1mu} ^{{\rm{th}}}}$ wire, what should we do ?

Two cells when connected in series are balanced on 8 m on a potentiometer. If the cells are connected with polarities of one of the cells reversed, they balance on 2 m. The ratio of e.m.f.'s of the two cells is

In a potentiometer experiment for measuring the emf of a cell, the null point is at ${\rm{480}}\,\,{\rm{cm}}$ when we have a $400\,\,{\rm{\Omega }}$ resistor in series with the cell and galvanometer. If the series resistances is reduced to half, the null point will be at

The length of a wire of a potentiometer is ${\rm{100}}\,\,{\rm{cm}}$, and the emf of its stand and cell is $E$ volt. It is employed to measure the emf of a battery whose internal resistance is ${\rm{0}}{\rm{.5}}\,\,{\rm{\Omega }}$. If the balance point is obtained at $l\,{\rm{ = }}\,{\rm{30}}\,\,{\rm{cm}}$ from the positive end, the emf of the battery is

In a potentiometer circuit a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire, the balance point occurs?

The emf of a battery '$A$' is balanced by a length of $80\,cm$ on a potentiometer wire. The emf of a

standard cell $1V$ is balanced by $50cm$. The emf of '$A$' is

In a potentiometer experiment, the balancing length with a cell is $560\,cm$. When an external resistance of $10\,\Omega$ is connected in parallel to the cell the balancing length changes by $60\,cm$. The internal resistance of the cell in ohm is

In a potentiometer circuit, a cell of EMF 1.5 V gives a balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire will the balance point occur?

The balance point in a potentiometer circuit is at 60 cm when the cell has an EMF of 3 V. What will be the new balance point if the length of the potentiometer wire is doubled, keeping the EMF of the cell constant?

A potentiometer wire of length ${\rm{10}}\,\,{\rm{m}}$ and resistance ${\rm{20}}\,\,{\rm{\Omega }}$ is connected is series with a ${\rm{15}}\,\,{\rm{V}}$ battery and an external resistance ${\rm{40}}\,\,{\rm{\Omega }}$. A secondary cell of emf ${\rm{E}}$ in the secondary circuit is balanced by ${\rm{240}}\,\,{\rm{cm}}$ long the potentiometer wire. The emf ${\rm{E}}$ of the cell is