In a potentiometer experiment, the balancing length for a cell is found to be $l$. If the driver cell is replaced by another cell of double the emf, what will be the new balancing length, assuming all other parameters remain constant?

In a potentiometer circuit, a cell of EMF 1.5 V gives a balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire will the balance point occur?

In a potentiometer experiment, a balance point is found at 50 cm when using a standard cell of EMF 1.018 V. If the standard cell is replaced by a battery of unknown EMF and the balance point shifts to 72 cm, what is the EMF of the battery?

A potentiometer is being used to compare two cells of emfs $E_1$ and $E_2$. The balancing lengths are found to be $l_1$ and $l_2$ respectively. If a resistance R is connected across $E_2$, its balancing length changes to $l_3$. Which of the following relations must hold true?

In a potentiometer experiment, the balance point is achieved when no current flows through the galvanometer. This condition ensures accurate EMF measurement because:

Resistance of $100\,\,cm$ long potentiometer wire is $10\,\,{\rm{\Omega }}$, it is connected to a battery $\left( {2\,\,volt} \right)$ and a resistance $R$ in series. A source of $10\,\,mV$ gives null point at $40\,\,cm$ length, then external resistance $R$ is

A potentiometer wire of length $1\,\,m$ and resistance $10\,\,{\rm{\Omega }}$ is connected in series with a cell of $emf\,\,2\,\,V$ with internal resistance $1\,\,{\rm{\Omega }}$ and a resistance box including a resistance $R.$. If potential difference between the ends of the wire is $1\,\,mV$, the value of $R.$ is

A battery of ${\rm{6}}\,\,{\rm{volts}}$ is connected to the terminals of a three metre long wire of uniform thickness and resistance of the order of ${\rm{100}}\,\,{\rm{\Omega }}$ . The difference of potential between two points separated by $50\,\,cm$ on the wire will be

In a potentiometer, the null point is obtained at a length of 40 cm when the cell in the secondary circuit has an emf of 1.5 V. If the length of the potentiometer wire is 1 m, what is the potential gradient?

A potentiometer wire of length $L$ and resistance $10\,\,{\rm{\Omega }}$ is connected in series with a battery of e.m.f. $2.5\,\,V$ and a resistance in its primary circuit. The null point corresponding to a cell of e.m.f. $1\,V$ is obtained at a distance $\frac{L}{2}$. If the resistance in the primary circuit is doubled then the position of new null point will be

A potentiometer wire of 100 cm balances the EMF of a cell at 40 cm. If a resistance of 10 Ω is connected across the cell, the balancing length shifts to 32 cm. What is the internal resistance of the cell?