A potentiometer wire of length 1 m has a resistance of 10 Ω. A cell of emf 2 V and negligible internal resistance is connected to the wire. What is the potential gradient across the wire?

A potentiometer is being used to compare two cells of emfs $E_1$ and $E_2$. The balancing lengths are found to be $l_1$ and $l_2$ respectively. If a resistance R is connected across $E_2$, its balancing length changes to $l_3$. Which of the following relations must hold true?

The accurate measurement of emf can be obtained using

In a potentiometer experiment, two cells when connected in series, first to support and then to oppose each other, give balancing lengths of 72 cm and 18 cm respectively on the potentiometer wire. Calculate the ratio of their EMFs.

In a potentiometer experiment, the balance point is achieved when no current flows through the galvanometer. This condition ensures accurate EMF measurement because:

When a Daniel cell is connected in the secondary circuit of a potentiometer, the balancing length is found to be ${\rm{540}}\,\,{\rm{cm}}$. If the balancing length becomes ${\rm{500}}\,\,{\rm{cm}}$ when the cell is short circuited with $1\,\,{\rm{\Omega }}$, the internal of the cell is

Two cells of EMFs $E_1$ and $E_2$ are connected in series with a potentiometer wire of length 2 meters. When the cells support each other, the balancing length is 140 cm. When they oppose each other, the balancing length is 20 cm. Determine the ratio $E_1/E_2$.

In a potentiometer experiment when a battery of emf $2V$ is included in the secondary circuit, the balance point is $500\,cm$. Find the balancing length of the same end when a cadmium cell of emf $1.018V$ is connected to the secondary circuit.

A potentiometer wire of length $L$ and resistance $10\,\,{\rm{\Omega }}$ is connected in series with a battery of e.m.f. $2.5\,\,V$ and a resistance in its primary circuit. The null point corresponding to a cell of e.m.f. $1\,V$ is obtained at a distance $\frac{L}{2}$. If the resistance in the primary circuit is doubled then the position of new null point will be

In a potentiometer experiment the balancing with a cell is at length ${\rm{240}}\,\,{\rm{cm}}$. on shunting the cell with a resistance of ${\rm{2}}\,\,{\rm{\Omega }}$, the balancing length becomes ${\rm{120}}\,\,{\rm{cm}}$. the internal resistance of cell is

When a Daniel cell is connected in the secondary circuit of a potentiometer, the balancing length is found to be ${\rm{540}}\,\,{\rm{cm}}$. If the balancing length becomes ${\rm{500}}\,\,{\rm{cm}}$ when the cell is short circuited with $1\,\,{\rm{\Omega }}$, the internal of the cell is