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A variable resistor is connected across a battery of emf and internal resistance . For what value of is the power delivered to maximum?
A potentiometer wire of length and resistance is connected to a battery of EMF and internal resistance . A cell of EMF is balanced at a length . What is the internal resistance of the cell?
0
R/3
2R/3
R
A potentiometer wire AB is 100 cm long and has a total resistance of 10Ξ©. It is connected to a driver cell of emf E and internal resistance r. When a cell of emf is balanced against a length of , the current through the potentiometer wire is . When the cell is shunted by a resistance of 10Ξ© and balanced against a length , the current through the potentiometer wire is . Which of the following is true?
iβlβ = iβlβ
iβlβ = 2iβlβ
2iβlβ = iβlβ
iβlβ = 0.5iβlβ
A potentiometer is being used to compare two cells of emfs and . The balancing lengths are found to be and respectively. If a resistance R is connected across , its balancing length changes to . Which of the following relations must hold true?
and
and
and
and
Two cells of emf and and internal resistances and respectively are connected in parallel. The equivalent emf and internal resistance of the combination will be:
,
,
,
,
A potentiometer wire of length 100cm has a resistance of 10Ξ©. It is connected in series with a resistance R and a cell of emf 2V and negligible internal resistance. A source of emf 10mV is balanced against a length of 40cm of the potentiometer wire. What is the value of the resistance R?
790Ξ©
990Ξ©
1000Ξ©
820Ξ©
A cell of emf E and internal resistance r is connected across a variable external resistance R. The graph of terminal potential difference V against current I reaches a maximum value of V. What is the relationship between E, r, and this maximum value of V?
V = E/2
V = E
V = 2E
V = E/r