If the frequency of incident light on a photocell is doubled, keeping the intensity constant, how does the stopping potential change?

A photocell is connected in series with a variable resistor and a sensitive ammeter. The cathode of the photocell is illuminated with monochromatic light of constant intensity. As the resistance of the variable resistor is increased, what happens to the photocurrent and the stopping potential?

The current in a photocell is directly proportional to the:

Maximum velocity of photoelectron emitted is $4.8{\rm{\;m}}{{\rm{s}}^{ - 1}}$. The $e/m$ ratio of electron is $1.76 imes {10^{11}}\;{\rm{Ck}}{{\rm{g}}^{ - 1}}$, then stopping potential is given by

The maximum velocity of the photoelectrons emitted from the surface is v when light of frequency n falls on a metal surface. If the incident frequency is increased to $3\mu$, the maximum velocity of the ejected photoelectrons will be

A photo cell is receiving light from a source placed at a distance of $1\;m.$ If the same source is to be placed at a distance of $2\;m,$ then the ejected electron

Photocells are used in which of the following applications?

The ratio of the de Broglie wavelengths of an electron of energy $10\;eV$ to that of person of mass $66\;kg$ travelling at a speed of $100\;km/hr$ is of the order of

Photo cell is a device to

When the light source is kept $20\;cm$ away from a photo cell, stopping potential $0.6\;V$ is obtained. When source is kept $40\;cm$ away, the stopping potential will be

The ratio of the de Broglie wavelengths of an electron of energy $10\;eV$ to that of person of mass $66\;kg$ travelling at a speed of $100\;km/hr$ is of the order of