The work function of a metal is . Light of frequency $2
u
u = \frac{\phi}{h}\frac{3
u}{2}$, and the intensity is doubled, what will be the ratio of the new saturation current to the original saturation current?
1/2
1
2
4
Related Questions
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A photocell is illuminated by a monochromatic light source with intensity and frequency $
u$. If the intensity is doubled while keeping the frequency constant, which of the following statements is TRUE regarding the photocurrent and stopping potential?
The photocurrent doubles, and the stopping potential remains the same.
The photocurrent remains the same, and the stopping potential doubles.
Both the photocurrent and stopping potential double.
Both the photocurrent and stopping potential remain the same.