Two different metals M1 and M2 have work functions and respectively, where . If both metals are illuminated with light of the same frequency $
uh
u > \phi_1$, which metal will exhibit a larger stopping potential?
M1
M2
Both will have the same stopping potential
Cannot be determined without knowing the intensity of light
Related Questions
Which factor affects the maximum kinetic energy of photoelectrons emitted in Lenard's experiment?
Intensity of incident light
Frequency of incident light
Material of the cathode
Both intensity and frequency of incident light
The kinetic energy of an electron, which is accelerated in the potential difference of 100 V, is
J
J
J
J
The electrons are emitted in the photoelectric effect from a metal surface
Only if the frequency of the incident radiation is above a certain threshold value
Only if the temperature of the surface is high
At a rate that is independent of the nature of the metal
With a maximum velocity proportional to the frequency of the incident radiation
The colour of the positive column in a gas discharge tube depends on
The type of glass used to construct the tube
The gas in the tube
The applied voltage
The material of the cathode
When yellow light is incident on a surface, no electrons are emitted while green light can emit. If red light is incident on the surface, then
No electrons are emitted
Photons are emitted
Electrons of higher energy are emitted
Electrons of lower energy are emitted
When ultraviolet rays are incident on metal plate, then photoelectric effect does not occur. It occurs by the incidence of
-rays
Radio wave
Infrared rays
Green house effect
When intensity of incident light increases
Photo-current increases
Photo-current decreases
Kinetic energy of emitted photoelectrons increases
Kinetic energy of emitted photoelectrons decreases
Light of frequency times the threshold frequency is incident on a photosensitive material. What will be the photoelectric current if the frequency is halved and intensity is doubled ?
doubled
four times
one-fourth
zero
The photoelectric effect represents that
Light has a particle nature
Electron has a wave nature
Proton has a wave nature
None of the above
The variation of photoelectric current given by the photocell, with the intensity of light, is give by a graph, which is a straight line with
ve slope with intercept on current axis
ve slope with intercept of current axis
ve slope passing through origin
ve slope passing through origin
