A negatively charged dust particle of mass $m$ and charge $-q$ falls from rest through a vertical distance $h$ in a uniform electric field $E$ directed upwards. What is the time taken for the dust particle to fall this distance?

An electron initially at rest falls a distance of $1.5\;cm$ in a uniform electric field of magnitude $2 imes {10^4}N/C$ The time taken by the electron to fall this distance is

The force experienced by a charged particle in a uniform electric field is:

A negatively charged particle is released from rest in a uniform electric field. Which of the following graphs correctly represents its potential energy as a function of position along the field lines?

Which of the following is deflected by electric field

Two identical charged spheres, each of mass $m$, are suspended from a common point by two massless strings of length $l$. They are initially at a distance $d (d << l)$ apart due to mutual repulsion. The charges begin to leak from both spheres at a constant rate. As a result, the spheres approach each other with a velocity $v$. How does $v$ vary as a function of the distance $x$ between the spheres?

Under the influence of the Coulomb field of charge $+ Q,$ a charge $- q$ is moving around it in an elliptical orbit. Find out the correct statement(s)

A pendulum bob carries a negative charge –$q$ .A positive charge + $q$ is held at the point of support. Then, the time period of the bob is

n identical mercury droplets charged to the same potential $V$ coalesce to form a single bigger drop. The potential of new drop will be

Under the action of a given coulombic force the acceleration of an electron is $2.5 imes {10^{22}}{\rm{m}}/{{\rm{s}}^2}.$ Then the magnitude of acceleration of a proton under the action of same force is nearly

Two identical charged spheres suspended from a common point by two massless strings of length $l$ are initially a distance d(d &lt; &lt; l) apart because of their mutual repulsion. The charge begins to leak from both the spheres at a constant rate. As a result the charges approach each other with a velocity $v$. Then as a function of distance $x$ between them