A charged particle of mass $m$ and charge $q$ enters a region of uniform electric field $E$ with a velocity $v$ perpendicular to the field. The time taken by the particle to traverse a distance $d$ along the field direction is:

A pendulum bob carries a negative charge $- q$. A positive charge $+ q$ is held at the point of support. Then, the time period of the bob is

When a negative charge is taken at a height from earth’s surface, then its potential energy

An electron enters in an electric field with its velocity in the direction of the electric lines of force. Then

A drop of ${10^{ - 6}}\;kg$ water carries ${10^{ - 6}}C$ charge. What electric field should be applied to balance its weight (assume $g = 10\;m/{s^2}$)

A particle of mass $m$ and charge $q$ is placed at rest in a uniform electric field $E$ and then released. The kinetic energy attained by the particle after moving a distance $y$ is

A simple pendulum has a length $l$ and the mass of the bob is $m$. The bob is given a charge $q$ coulomb. The pendulum is suspended between the vertical plates of a charged parallel plate capacitor. If $E$ is the electric field strength between the plates, the time period of the pendulum is given by

An electron enters a uniform electric field $E$ with an initial velocity $v_0$ perpendicular to the field. What is the trajectory of the electron?

The charge $q$ is projected into a uniform electric field $E,$ work done when it moves a distance $Y$ is

An electron of mass $m$ and charge $e$ is accelerated from rest through a potential difference $V$ in vacuum. The final speed of the electron will be

A charged particle is released from rest in a uniform electric field. Its kinetic energy after time $t$ is proportional to: