A parallel plate capacitor with capacitance C is charged to a potential V. It is then disconnected from the battery and the distance between the plates is doubled. What happens to the energy stored in the capacitor?

64 identical spheres of charge $q$ and capacitance $C$ each are combined to form a large sphere. The charge and capacitance of the large sphere is

A capacitor of capacitance $C$ carrying charge $Q$ is connected to a source of emf $E$. Finally, the charge on capacitor would be

The two spherical shells are at large separation one of them has radius $10 \mathrm{~cm}$ and has $1.25 \mu \mathrm{C}$ charge. The other is of $20 \mathrm{~cm}$ radius and has $0.75 \mu \mathrm{C}$ charge. If they are connected by a conducting wire of negligible capacity, the charge on the shells are-

Capacity of parallel plate capacitor in air and on immersing it into oil is $50 \,{mF}$ and $110 \,{mF}$ respectively. The dielectric constant of oil is

$n$ identical droplets are charged to $V$ volt each. If they coalesce to form a single drop, then its potential will be

The radius of a sphere of capacity $1\,\,\mu F$ in air is

A capacitor of capacitance $9 \mathrm{~nF}$ having dielectric slab of ${\varepsilon _r}=2.4,$ dielectric strength $20 \mathrm{~MV} / \mathrm{m}$ and $P.D. = 20 \mathrm{~V}$ calculate area of plates.

An electric dipole is placed at an angle of $30^\circ$ with an electric field of intensity $2 imes {10^5}N/C.$ It experiences a torque equal to 4 Nm. Calculate the charge on the dipole if the dipole length is 2 cm:-

Two identical parallel plate capacitors, A and B, are connected to a battery. The distance between the plates of capacitor A is half that of capacitor B. Which capacitor stores more energy?

Assertion: In the absence of an external electric field, the dipole moment per unit volume of polar dielectric is zero.

Reason: The dipoles of a polar dielectric are randomly oriented.