A parallel plate capacitor is filled with two dielectrics of permittivities and , each occupying half the volume as shown. If the area of each plate is A and the plate separation is d, what is the capacitance?
\frac{(\epsilon_1 + \epsilon_2)A}{2d}
\frac{\epsilon_1 \epsilon_2 A}{(\epsilon_1 + \epsilon_2)d}
\frac{2\epsilon_1 \epsilon_2 A}{(\epsilon_1 + \epsilon_2)d}
\frac{(\epsilon_1 + \epsilon_2)A}{d}
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A parallel plate capacitor is filled with two dielectrics of permittivities and , each occupying half the volume as shown. If the area of each plate is A and the plate separation is d, what is the capacitance?
\frac{(\epsilon_1 + \epsilon_2)A}{2d}
\frac{\epsilon_1 \epsilon_2 A}{(\epsilon_1 + \epsilon_2)d}
\frac{2\epsilon_1 \epsilon_2 A}{(\epsilon_1 + \epsilon_2)d}
\frac{(\epsilon_1 + \epsilon_2)A}{d}
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