A parallel plate capacitor is being charged by a constant current $I$. The area of the plates is $A$ and the separation is $d$. The displacement current density between the plates is:

Assertion:- When a capacitor is charged by a battery, both the plates receive charges equal in magnitude, no matter whether the sizes of plates are identical or not. Reason:- The charge distribution on the plates of a capacitor is in accordance with the charge conservation principle.

A parallel plate capacitor is charged and then disconnected from the battery. If a dielectric slab is then inserted between the plates, which quantity remains constant?

A parallel plate capacitor with air between the plates has a capacitance of $8 \mathrm{~pF}$. Calculate the capacitance if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant: $\left(\varepsilon_r=6\right)$

The plates of a parallel plate condenser are pulled apart with a velocity $v.$ If at any instant their mutual distance of separation is $d,$ then the magnitude of the time of rate of change of capacity depends on $d$ as follows

A parallel plate capacitor is charged. If the plates are pulled apart

The mean electric energy density between the plates of a charged capacitor is (here $q =$ charge on the capacitor and $A =$ area of the capacitor plate)

Two identical thin metal plates has charge $q_1$ and $q_2$ respectively such that $q_1>q_2$. The plates were brought close to each other to form a parallel plate capacitor of capacitance $C$. The potential difference between them is

A dielectric of dielectric constant $ext{K}$ is introduced such that half of area of capacitor of capacity $ext{C}$ is occupied by it. The new capacity is

A parallel plate capacitor has capacitance of $2\mu F$ in air and $12\mu F$ when immersed in oil. The dielectric constant of oil

Two parallel metal plates carry opposite electrical charges each with a magnitude of $Q$. The plates are separated by a distance $d$ and each plate has an area $A$. Consider the following:

(I) increasing $Q$

(II) increasing ${d}$

(III) increasing $A$

Which of the following would have the effect of reducing the potential difference between the plates?