A particle is projected from the surface of a non-rotating planet of radius R with escape velocity. Neglecting atmospheric resistance, which of the following best describes the path of the particle?

The mass of planet mars is $\frac{1}{10}$ th of the mass of earth and radius is $\frac{1}{2}$ of the radius of earth. If the escape velocity at the earth is $11.2 \mathrm{~km} / \mathrm{s}$, then the escape velocity at Mars will be

The escape velocity of a body from the earth’s surface is ${V_e}$. The escape velocity of the same body from a height equal to 7R from the earth’s surface will be

Gravitational force between two point masses is found to be F when both are in vacuum. If both the masses are immersed in water, new gravitational force will be

The escape velocity on a planet is . If the radius of the planet contracts to $\frac{1}{4}th$ the present value without any change in its mass, then the escape velocity becomes

On which quantity the escape velocity for earth does not depend on

The escape velocity of a body projected from the surface of earth is $v_e$. If the body is projected at an angle $heta$ to the horizontal surface of earth, then the escape velocity would be

The escape velocity from the Earth's surface is $v$. The escape velocity from the surface of another planet having a radius four times that of Earth and the same mass density is:

A planet has a mean density one-fourth that of Earth and a radius twice that of Earth. What is the escape velocity from this planet if the escape velocity from Earth is $v_e$?

Planet X has a radius four times that of Earth and a mean density half that of Earth. Determine the ratio of the escape velocity from Earth ($v_e$) to the escape velocity from Planet X ($v_x$).

If a planet has a radius three times and mean density one-third that of Earth, what is the ratio of the escape velocity from Earth ($v_e$) to the escape velocity from the planet ($v_p$)?