If Earth's density were doubled while its radius remained constant, the acceleration due to gravity at its surface would:

On the surface of a planet of mass $M$ and radius $R$, the acceleration due to gravity is $g$. If we go on another planet of same density but half the radius then on the new planet, the acceleration due to gravity

A body of mass 5 kg is moving in a circle of radius 1 m with an angular velocity of 2 ${\rm{rad\;}}{{\rm{s}}^{ - 1}}$. The centripetal force, is

The radius of the earth is $6400 \mathrm{~km}$ and $g=10 \mathrm{~m} / \mathrm{sec}^2$. In order that a body of $5 \mathrm{~kg}$ weighs zero at the equator, the angular speed of the earth is

An object experiences a gravitational force of $100$ N on the surface of the earth. What is the gravitational force on it at a height equal to one-third the radius of the earth?

The earth moves round the sun in a near circular orbit of radius $1.5 imes {10^{11}}$ m. Its centripetal acceleration is

Which of the following statements is true about 'G'?

The planets with radii $R_1$ and $R_2$ have densities $\rho_1$ and $\rho_2$, respectively. Their atmospheric pressures are $p_1$ and $p_2$, respectively. Therefore, the ratio of masses of their atmospheres, neglecting variation of $g$ within the limits of atmosphere is

The binding energy of an object of mass $m$ placed on the surface of the earth is $(R=$ radius of earth, $g=$ acceleration. due to gravity)

Consider a planet in solar system which has the mass double mass of the earth and density equal to the average density of the earth. An object weighing $\mathrm{W}$ on the earth will weight

A satellite experiences a gravitational force of $500$ N at a height equal to the radius of the earth. What would be the gravitational force on it on the earth's surface?