If Earth's radius were doubled while its mass remained constant, the acceleration due to gravity at its surface would:

The height at which the value of '$g$' is half that on the surface of the earth of radius R is

With what velocity should a particle be projected so that its height becomes equal to radius of earth?

The acceleration due to gravity at a depth 'd' from the Earth's surface is given by?

If the diameter of earth becomes half keeping mass to be constant, then the acceleration due to gravity at surface of earth becomes

The earth is an approximately sphere. If the

interior contained matter which is not of the

same density everywhere, then on the surface

of the earth, the acceleration due to gravity:

An iron ball and a wooden ball of the same radius are released from a beight $h$ in vacuum. The time taken by both to reach the ground is. The correct option is:

The acceleration due to gravity at the poles and the equator is $g_p$ and $g_e$ respectively. If the earth is a sphere of radius ${Re}$ and rotation about its axis with angular speed $\omega$, then $g_p-g_e$ is given by :-

Given mass of the moon is $1 / 81$ of the mass of the earth and corresponding radius is $1 / 4$ of the earth. If escape velocity on the earth surface is $11.2 {~km} / {s}$, the value of same on the surface of the moon is

At what height above the earth's surface, the value of $g$ is half of its value on earth's surface? Given its radius is $6400 \mathrm{~km}$

A cycle wheel of radius 0.4 m completes one revolution in one second then the acceleration of a point on the cycle wheel will be